p=(p*4*9)/100-(p*2*12)/100 = 480
=12p/100=480
p=4000
It is given that the initial amount invested in scheme A is Rs P at 10%per Annum S.I. =PTR/100 = P x 10 x 2/100 Now the total amount after 2 years is = 1.2P New Rate of interest = 12% per annum Time = 5 years S.I for next 5 years when new principal amount is 1.2 P = 1.2Px12x5/100 = 0.72P Total amount after 5 years at 12% per annun = 1.72P Given that 1.72P - 1.2P = 1300 P = 1300/0.52 P = Rs. 2500
Let time period of S.I. be T years.
Then for a principal amount, say P,
ATQ, as, S.I. = C.I. for rate =10%p.a. and
time for C.I. = 2(P x 10 x T)/100 = P{[ (100+10)/100 ]2-1}T/10 = [ 110/100 ]2?1 = [(11/10)2?1] = (121-100)/100T/10 = 21/100T = 21/10 = 2.1 years
10000/16 = X/4(1*1+2*3+4*9+8*27)
10000/16=X/4(1+6+36+216)
X=647500
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.