P = Rs. 900, R = 3 ½ % = 7/2 %, T = 2 years.
Therefore,
S.I. = PTR/100
S.I. = Rs. (900 x 7/2 x 2/100) = Rs. 63
Now, P = Rs. 200, S.I. = Rs. 63, R = 5 %
Time = ((100 x 63) / (200 x 5) ) years = 6.3 years.
I = (600x11x5)/100 = 330 Paise = Rs. 3.30
Given,
S.I = 3 Principal Amount
=> 3A = A x 16 x R/100
By solving, we get
=> R = 18.75%
Present worth = 169/(1+4/100)^n = 156.25
Given : S.I. = Rs. 50.
I gives, R = 10% p.a.
II gives, T = 10 years.
Sum = (100 x S.I)/(t x r ) = Rs.(100 x 50)/(10 x 10) = Rs.50
I=
I=prt
Now, the principal amount P = Rs. 1,45,440
Rate of interest R = 20%/annum
Now monthly income I = PTR/100 = 1,45,440 x 20 x 1/100 x 12
= 2908800/1200
= Rs. 2424.
Hence, her monthly income = Rs. 2424.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.