As the interest rate increases by 2%
=> (7000x3x2)/100 = 420
9200
--------
9620
We know that I = PTR/100
=> P = 20250/4.5 = 4500
Now, new Interest at 5% = 4500x1x5/100 = 225
Now the additional amount = 225 - 202.5 = Rs. 22.5
S.I. = Rs. (15500 - 12500) = Rs. 3000.
Rate = % = 6%
Let the principle amount be Rs. P
Interest rate = 12%
Total amount he paid after 5 years = Rs. 1280
ATQ,
Hence, the amount he borrowed = P = Rs. 800.
Let the sum invested be Rs. P
Let the rate of interest be R% per annum
=> Interest earned for 5 years = (P x 5 x R/100) = PR/20
Now, given that the interest earned increased by Rs. 600 if the Rate increased to (R+2)%
=> SI = (P x 5 x (R+2))/100 = PR/20 + 10P/100
Hence,
PR/20 + 10P/100 = PR/20 + 600
=> P = 6000
Therefore, the sum invested is Rs. 6000
S.I. for 3 years = Rs. (12005 - 9800) = Rs. 2205.
S.I. for 5 years = Rs. = Rs.3675
Principle = Rs.(9800-3675) = Rs.6125
Hence, Rate = =12%
Let man invested Rs. A And, after two years amount invested = (A +
Let the sum be Rs. 100. Then,
S.I. for first 6 months = Rs.[ (100 x 10 x 1)/(100 x 2) ]= Rs.5
S.I. for last 6 months =Rs.[(102 x 10 x 1)/(100 x 2) ] = Rs.5.25
So, amount at the end of 1 year = Rs. (100 + 5 + 5.25) = Rs. 110.25
Effective rate = (110.25 - 100) = 10.25%
Let the principal be P and rate of interest be R%.
Required ratio =
(kx5x1)/100 + [(1500 - k)x6x1]/100 = 85
5k/100 + 90 ? 6k/100 = 85
k/100 = 5
=> k = 500
Let sum = S. Then, amount = 7S/6
S.I. = 7S/6 - S = S/6; Time = 3 years.
Rate = (100 x S) / (S x 6 x 3) = 5 5/9 = 50/9 %.
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