Manju borrows Rs. 5000 for 2 years at 4% p.a. simple interest
She also lends it at 6 1?4% p.a for 2 years
=> Total Gain = 6 1/4% ? 4% = 2 1/4%
So her gain in the transaction for 1 year
= The simple interest she gets for Rs.5000 for 1 year at 2 1?4% per annum
= = Rs. 112.5/ year.
I = PTR/100
I = 25 x 4 x 0.03/100
I = 0.03 x 100 = 300 Ps = Rs. 3
Let the sum at 15% be Rs x and that at 18% be Rs (24000 - x).
{(x * 15 * 1)/100 } + { [(24000 ? x) * 18 * 1]/100 } = 4050
or 15 x + 432000 - 18x = 405000 or x = 9000.
Money borrowed at 15% = Rs 9000 .
Money borrowed at 18% = Rs 15000.
Given that Rs. 1860 will become Rs. 2641.20 at 12%
=> Simple Interest = 2641.20 - 1860 = Rs. 781.20
We know I = PTR/100
=> 781.20 x 100 = 1860 x T x 12
=> T = 78120/1860x12
=> T = 78120/22320
=> T = 3.5 years.
Simple interest is given by the formula SI = (pnr/100), where p is the principal, n is the numberof years for which it is invested, r is the rate of interest per annum
In this case, Rs. 1250 has become Rs.10,000.
Therefore, the interest earned = 10,000 ? 1250 = 8750.
8750 = [(1250 x n x 12.5)/100]
=> n = 700 / 12.5 = 56 years.
Amount to be paid = = Rs. 115.
Let the interest rate be r%
We know that,
S.I = PTR/100
=> (1540 x 5 x r)/100 + (1800 x 4 x r)/100 = 1788
=> r = 178800/14900 = 12%
Let the required Sum = Rs.S
From the given data,
1008 = [(S x 11 x 5)/100] - [(S x 8 x 6)/100]
=> S = Rs. 14,400.
Here given Interest earned = Rs. 2260
Time = 3 years
Rate of interest = ?
Principal Amount = ?
So, it can't be determined.
P --- 10 ----- 600
P --- 5 ----- 300
3P --- 5 ----- 900
__________
1200
(24 + 31 + 18) days = 73 days = 1/5 year .
P = Rs 3000 and R = 18 % p.a.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.