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- Question
In what time will Rs. 1860 amount to Rs. 2641.20 at simple interest 12% per annum?
Options- A. 2.9 years
- B. 3.5 years
- C. 4.2 years
- D. 4.7 years
- Correct Answer
- 3.5 years
ExplanationGiven that Rs. 1860 will become Rs. 2641.20 at 12%
=> Simple Interest = 2641.20 - 1860 = Rs. 781.20
We know I = PTR/100
=> 781.20 x 100 = 1860 x T x 12
=> T = 78120/1860x12
=> T = 78120/22320
=> T = 3.5 years.
- 1. How long will it take for a sum of money to grow from Rs.1250 to Rs.10,000, if it is invested at 12.5% p.a simple interest?
Options- A. 65years
- B. 56years
- C. 45years
- D. 57years Discuss
- 2. A person takes a loan of Rs. 200 at 5% simple interest. He returns Rs.100 at the end of one year. In order clear his dues at the end of 2 years, he would pay :
Options- A. Rs. 100
- B. Rs. 105
- C. Rs. 115
- D. Rs. 110 Discuss
- 3. If the C.I. on a sum for 2 years at 12 1/2 % per annum is Rs. 510, the S.I. on the same sum at the same rate for the same period of time is ?
Options- A. Rs. 580
- B. Rs. 480
- C. Rs. 550
- D. Rs. 470 Discuss
- 4. A sum was put at simple interest at a certain rate for 10 years . Had it been put at 5% higher rate , it would have fetched Rs.600 more. What was the Sum?
Options- A. Rs.1200
- B. Rs.1300
- C. Rs.1400
- D. Rs.1500 Discuss
- 5. A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 more is lent but at the rate twice the former. At the end of the year, Rs. 33.50 is earned as interest from both the loans. What was the original rate of interest?
Options- A. 3.46%
- B. 4.5%
- C. 5%
- D. 6% Discuss
- 6. A man borrowed Rs 24000 from two money lenders. For one loan, he paid 15% per annum and for the other 18% per annum. At the end of one year, he paid Rs 4050. How much did he borrow at each rate ?
Options- A. Rs.16000
- B. Rs.12000
- C. Rs.15000
- D. Rs.13000 Discuss
- 7. The simple interest on Rs. 25 for 4 months at the rate of 3 paise per rupee per month is :
Options- A. 240 paise
- B. Rs. 1.40
- C. Rs. 2.20
- D. Rs. 3 Discuss
- 8. Manju borrows Rs.5000 for 2 years at 4% p.a. simple interest from Sudha. She immediately lends it to another person at 6 1?4% p.a for 2 years. Find her gain in the transaction per year.
Options- A. Rs. 101
- B. Rs. 98.5
- C. Rs. 124.3
- D. Rs. 112.5 Discuss
- 9. A person lends Rs. 1540 for five years and Rs. 1800 for four years. If he gets Rs. 1788 as interest on both amounts, what is the rate of interest ?
Options- A. 14.5%
- B. 11%
- C. 12%
- D. 10.5% Discuss
- 10. Two equal sums were lent, one at the rate of 11% per annum for five years and the other at the rate of 8% per annum for six years, both under simple interest. If the difference in interest accrued in the two cases is Rs 1008. Find the sum?
Options- A. Rs. 14,400
- B. Rs. 15,600
- C. Rs. 14,850
- D. Rs. 15,220 Discuss
Simple Interest problems
Search Results
Correct Answer: 56years
Explanation:
Simple interest is given by the formula SI = (pnr/100), where p is the principal, n is the numberof years for which it is invested, r is the rate of interest per annum
In this case, Rs. 1250 has become Rs.10,000.
Therefore, the interest earned = 10,000 ? 1250 = 8750.
8750 = [(1250 x n x 12.5)/100]
=> n = 700 / 12.5 = 56 years.
Correct Answer: Rs. 115
Explanation:
Amount to be paid = = Rs. 115.
Correct Answer: Rs. 480
Explanation:
Let the sum be Rs. P. Then,
= 510
P[ - 1] = 510.
Sum = Rs. 1920
So, S.I. = (1920 x 25 x 2) / (2 x 100) = Rs. 480
Correct Answer: Rs.1200
Explanation:
At 5% more rate, the increase in S.I for 10 years = Rs.600 (given)
So, at 5% more rate, the increase in SI for 1 year = 600/10 = Rs.60/-
i.e. Rs.60 is 5% of the invested sum
So, 1% of the invested sum = 60/5
Therefore, the invested sum = 60 × 100/5 = Rs.1200
Correct Answer: 3.46%
Explanation:
Let the original rate be R%. Then, new rate = (2R)%.
Note: Here, original rate is for 1 year(s); the new rate is for only 4 months i.e.1/3 year(s).
=> (2175 + 725) R = 33.50 x 100 x 3
=> (2175 + 725) R = 10050
=> (2900)R = 10050
=>
Original rate = 3.46%
Correct Answer: Rs.15000
Explanation:
Let the sum at 15% be Rs x and that at 18% be Rs (24000 - x).
{(x * 15 * 1)/100 } + { [(24000 ? x) * 18 * 1]/100 } = 4050
or 15 x + 432000 - 18x = 405000 or x = 9000.
Money borrowed at 15% = Rs 9000 .
Money borrowed at 18% = Rs 15000.
Correct Answer: Rs. 3
Explanation:
I = PTR/100
I = 25 x 4 x 0.03/100
I = 0.03 x 100 = 300 Ps = Rs. 3
Correct Answer: Rs. 112.5
Explanation:
Manju borrows Rs. 5000 for 2 years at 4% p.a. simple interest
She also lends it at 6 1?4% p.a for 2 years
=> Total Gain = 6 1/4% ? 4% = 2 1/4%
So her gain in the transaction for 1 year
= The simple interest she gets for Rs.5000 for 1 year at 2 1?4% per annum
= = Rs. 112.5/ year.
Correct Answer: 12%
Explanation:
Let the interest rate be r%
We know that,
S.I = PTR/100
=> (1540 x 5 x r)/100 + (1800 x 4 x r)/100 = 1788
=> r = 178800/14900 = 12%
Correct Answer: Rs. 14,400
Explanation:
Let the required Sum = Rs.S
From the given data,
1008 = [(S x 11 x 5)/100] - [(S x 8 x 6)/100]
=> S = Rs. 14,400.
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