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- Question
A person takes a loan of Rs. 200 at 5% simple interest. He returns Rs.100 at the end of one year. In order clear his dues at the end of 2 years, he would pay :
Options- A. Rs. 100
- B. Rs. 105
- C. Rs. 115
- D. Rs. 110
- Correct Answer
- Rs. 115
ExplanationAmount to be paid = = Rs. 115.
- 1. If the C.I. on a sum for 2 years at 12 1/2 % per annum is Rs. 510, the S.I. on the same sum at the same rate for the same period of time is ?
Options- A. Rs. 580
- B. Rs. 480
- C. Rs. 550
- D. Rs. 470 Discuss
- 2. A sum was put at simple interest at a certain rate for 10 years . Had it been put at 5% higher rate , it would have fetched Rs.600 more. What was the Sum?
Options- A. Rs.1200
- B. Rs.1300
- C. Rs.1400
- D. Rs.1500 Discuss
- 3. A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 more is lent but at the rate twice the former. At the end of the year, Rs. 33.50 is earned as interest from both the loans. What was the original rate of interest?
Options- A. 3.46%
- B. 4.5%
- C. 5%
- D. 6% Discuss
- 4. At what rate of compound interest per annum will a sum of rs.1200 becomes rs.1348.32 in 2 years
Options- A. 66%%
- B. 6.5%
- C. 7%
- D. 7.5% Discuss
- 5. A sum was put at simple interest at a certain rate for 3 years. Had it been put at 2% higher rate, it would have fetched Rs 360 more. Find the sum.
Options- A. Rs.4000
- B. Rs.9000
- C. Rs.5000
- D. Rs.6000 Discuss
- 6. How long will it take for a sum of money to grow from Rs.1250 to Rs.10,000, if it is invested at 12.5% p.a simple interest?
Options- A. 65years
- B. 56years
- C. 45years
- D. 57years Discuss
- 7. In what time will Rs. 1860 amount to Rs. 2641.20 at simple interest 12% per annum?
Options- A. 2.9 years
- B. 3.5 years
- C. 4.2 years
- D. 4.7 years Discuss
- 8. A man borrowed Rs 24000 from two money lenders. For one loan, he paid 15% per annum and for the other 18% per annum. At the end of one year, he paid Rs 4050. How much did he borrow at each rate ?
Options- A. Rs.16000
- B. Rs.12000
- C. Rs.15000
- D. Rs.13000 Discuss
- 9. The simple interest on Rs. 25 for 4 months at the rate of 3 paise per rupee per month is :
Options- A. 240 paise
- B. Rs. 1.40
- C. Rs. 2.20
- D. Rs. 3 Discuss
- 10. Manju borrows Rs.5000 for 2 years at 4% p.a. simple interest from Sudha. She immediately lends it to another person at 6 1?4% p.a for 2 years. Find her gain in the transaction per year.
Options- A. Rs. 101
- B. Rs. 98.5
- C. Rs. 124.3
- D. Rs. 112.5 Discuss
Simple Interest problems
Search Results
Correct Answer: Rs. 480
Explanation:
Let the sum be Rs. P. Then,
= 510
P[ - 1] = 510.
Sum = Rs. 1920
So, S.I. = (1920 x 25 x 2) / (2 x 100) = Rs. 480
Correct Answer: Rs.1200
Explanation:
At 5% more rate, the increase in S.I for 10 years = Rs.600 (given)
So, at 5% more rate, the increase in SI for 1 year = 600/10 = Rs.60/-
i.e. Rs.60 is 5% of the invested sum
So, 1% of the invested sum = 60/5
Therefore, the invested sum = 60 × 100/5 = Rs.1200
Correct Answer: 3.46%
Explanation:
Let the original rate be R%. Then, new rate = (2R)%.
Note: Here, original rate is for 1 year(s); the new rate is for only 4 months i.e.1/3 year(s).
=> (2175 + 725) R = 33.50 x 100 x 3
=> (2175 + 725) R = 10050
=> (2900)R = 10050
=>
Original rate = 3.46%
Correct Answer: 66%%
Explanation:
rate=r%
1200 (1+r/100)^2=1348.32
r=6%
Correct Answer: Rs.6000
Explanation:
Let sum = P and original rate = R. Then
[(P * (R+2) * 3)/100] - [ (P * R * 3)/100] = 360
3P*(R+2) - 3PR = 36000
3PR + 6P - 3PR = 36000
6P = 36000
P = 6000
Correct Answer: 56years
Explanation:
Simple interest is given by the formula SI = (pnr/100), where p is the principal, n is the numberof years for which it is invested, r is the rate of interest per annum
In this case, Rs. 1250 has become Rs.10,000.
Therefore, the interest earned = 10,000 ? 1250 = 8750.
8750 = [(1250 x n x 12.5)/100]
=> n = 700 / 12.5 = 56 years.
Correct Answer: 3.5 years
Explanation:
Given that Rs. 1860 will become Rs. 2641.20 at 12%
=> Simple Interest = 2641.20 - 1860 = Rs. 781.20
We know I = PTR/100
=> 781.20 x 100 = 1860 x T x 12
=> T = 78120/1860x12
=> T = 78120/22320
=> T = 3.5 years.
Correct Answer: Rs.15000
Explanation:
Let the sum at 15% be Rs x and that at 18% be Rs (24000 - x).
{(x * 15 * 1)/100 } + { [(24000 ? x) * 18 * 1]/100 } = 4050
or 15 x + 432000 - 18x = 405000 or x = 9000.
Money borrowed at 15% = Rs 9000 .
Money borrowed at 18% = Rs 15000.
Correct Answer: Rs. 3
Explanation:
I = PTR/100
I = 25 x 4 x 0.03/100
I = 0.03 x 100 = 300 Ps = Rs. 3
Correct Answer: Rs. 112.5
Explanation:
Manju borrows Rs. 5000 for 2 years at 4% p.a. simple interest
She also lends it at 6 1?4% p.a for 2 years
=> Total Gain = 6 1/4% ? 4% = 2 1/4%
So her gain in the transaction for 1 year
= The simple interest she gets for Rs.5000 for 1 year at 2 1?4% per annum
= = Rs. 112.5/ year.
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