Let sum = X. Then S.I = 16x/25
Let rate = R% and Time = R years.
Therefore, (x * R * R)/100 = 16x/25 => R = 40/5 = 8
Therefore, Rate = 8% and Time = 8 years.
S.I. for 1 ½ years = Rs (1164 - 1008) = Rs 156 .
S.I. for 2 years = Rs (156 x x 2)= Rs 208.
Therefore, Principal = Rs (1008 - 208) = Rs 800.
Now, P = 800, T= 2 and S.I. = 208.
Therefore, Rate = (100 x S.I.) / (P x T) = [ (100 x 208)/(800 x 2)]% = 13%
Principal =
Let the time be 'n' years, Then
n = 3/2 or n= 1 Years
Let each instalment be Rs.x .
1st year = [x + (x * 12 * 2)/100]
2nd year = [ x + (x *12 * 1)/100]
3rd year = x
Then, [x + (x * 12 * 2)/100] + [ x + (x *12 * 1)/100] + x =1092
3x + ( 24x/100 ) + ( 12x/100 ) = 1092
336x =109200
Therefore, x = 325
Each instalment = Rs. 325
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698
= Rs. (625 - 400)
= Rs. 225
P = Rs. 6250, R = 14 % & T = (146/365) years = 2/5 years .
S.I=
let the sum lent at 5% be Rs.x and that lent at 8% be Rs.(1550-x). then,
Interest on x at 5% for 3 years + interest on (1550-x) at 8% for 3 years = 300
x=800
Required ratio = x : (1550-x) = 800 : (1550-800) = 800 : 750 = 16 : 15
Time = (100 x 81) / (450 x 4.5) = 4 years.
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