Discussion
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- Question
A sum is divided among K, L and M in such a way that for each rupee K gets, L gets 45 paisa and M gets 30 paisa. If the share of L is Rs. 27, what is the total amount ?
Options- A. Rs. 159
- B. Rs. 96
- C. Rs. 147
- D. Rs. 105
- Correct Answer
- Rs. 105
ExplanationK : L : M = 100 : 45 : 30
= 20 : 9 : 6Given L share is 27
=> 9 ------ 27
35 ------ ?=> 105
- 1. If Rs. 782 be divided into three parts, proportional to 1/2:2/3:3/4, then the first part is:
Options- A. Rs. 408
- B. Rs. 204
- C. Rs. 412
- D. Rs. 220 Discuss
- 2. A company requires 12,100 strength. Present employees are 400 ladies and 6400 gents. To reach the target how many ladies required to maintain the same ratio ?
Options- A. 400
- B. 600
- C. 900
- D. 700 Discuss
- 3. If k : l = 4 : 3 and l : m = 5 : 3, then find k : l : m ?
Options- A. 18 : 24 : 11
- B. 9 : 15 : 1
- C. 20 : 15 : 9
- D. 21 : 7 : 3 Discuss
- 4. The marks obtained by Vijay and Amith are in the ratio 4:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of ?
Options- A. 4:5
- B. 6:5
- C. 3:2
- D. 1:3 Discuss
- 5. What is the equivalent compound ratio of 5:6::7:10::6:5 ?
Options- A. 7 : 9
- B. 9 : 7
- C. 7 : 4
- D. 7 : 10 Discuss
- 6. Pooja, Shipra and Mounika are three sisters .Pooja and Shipra are twins. The ratio of sum of the ages of Pooja and Shipra is same as that of Mounika alone. Three years earlier the ratio of age of Pooja and Mounika was 2:7 . what will be the age of Shipra 3 years hence?
Options- A. 21 years
- B. 16 years
- C. 8 years
- D. 12 years Discuss
- 7. Total number of students in 3 classes of a school is 333 . The number of students in class 1 and 2 are in 3:5 ratio and 2 and 3 class are 7:11 ratio . What is the strength of class that has highest number of students ?
Options- A. 125
- B. 155
- C. 135
- D. 165 Discuss
- 8. At a game of billiards, A can give B 20 points in 60 and A can give C 15 points in 60. How many points can C give B in a game of 90 ?
Options- A. 9 points
- B. 10 points
- C. 11 points
- D. 8 points Discuss
- 9. The ratio between the number of sheep and the number of horses at the Stewar farm is 4 to 15. If each of horse is fed 110 ounces of horse food per day and the farm needs a total 13200 ounces of horse food per day. what is number sheep in the form ?
Options- A. 32
- B. 36
- C. 44
- D. 52 Discuss
- 10. What will be the average of the first 5 positive even numbers divisible by 9?
Options- A. 50
- B. 54
- C. 48
- D. 62 Discuss
Ratio and Proportion problems
Search Results
Correct Answer: Rs. 204
Explanation:
Given ratio = 1/2:2/3:3/4 = 6:8:9
1st part = 782 x 6/23 = Rs. 204.
Correct Answer: 900
Explanation:
6,400 gents, 2400 ladies in that company.
So total 8,800employees.
for 8,800 employees, we want 2400 ladies.
for 12,100employees we want how many ladies ?
=> (12,100/8,800) x 2400 = 3300.
So we want 3300 - 2400 = 900 more ladies.
Correct Answer: 20 : 15 : 9
Explanation:
Given k : l = 4 : 3
l : m = 5 : 3
Then k : l : m = 20 : 15 : 9
Correct Answer: 6:5
Explanation:
4:5
3:2
-------
=> 12:15:10
12:10
=> 6:5
Correct Answer: 7 : 10
Explanation:
Given 5:6 :: 7:10 :: 6:5
We know that compound ratio is calculated as
a:b :: c:d :: e:f
(axcxe):(bxdxf)
=> (5x7x6):(6x10x5)
=> (210):(300)
= 7:10
Correct Answer: 8 years
Explanation:
Since Pooja and Shipra are twins so their ages be same. Let their ages be x and age of Mounika be y , then
x+x = y -------(1)
and
Now, from equation (1),
7x - 4x = 15 => x = 5
So the age of Shipra 3 years hence will be 5+3 = 8 years
Correct Answer: 165
Explanation:
Ratio C1:C2 = 3:5 and C2:C3 = 7:11
So C1:C2:C3 = 21 : 35 : 55
Let the strength of three classes are 21x, 35x and 55x respectively, then
Given that 21x + 35x + 55x = 333
=> 111x = 333 or x=3
So strength of the class with highest number of students =55x = 55x3 = 165.
Correct Answer: 10 points
Explanation:
a:b = 60:40
a:c = 60:45
c/a x a/b = 45/60 x 60/40 = 45/40 = 90/80
So C gives B => 10 points.
Correct Answer: 32
Explanation:
Given ratio of number of sheep and horses = 4 : 15
Let number of sheep and horses are 4k and 15k
Number of horses = 13200/110 = 120
Now 15K = 120 and k = 8
Number of sheep = 4k = (4 x 8) = 32
Correct Answer: 54
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