504/M = 384/800
(504 x 800) / 384 = M
M = 1050
Given the salaries are in the ratio of 4 : 5 : 6
Now the salaries are increased by 50%, 60% and 50% respectively
The New ratio of salaries will be
4 x (150/100) : 5 x (160/100) : 6 x (150/100)
= 6 : 8 : 9
The new ratio of salaries of Akhil, Arun and Karthik is 9 : 8 : 6
Given total applicants = 135
Given graduates are G=60
Otherthan graduates=135-60 = 75
Given experienced candidates = 80
1) For maximum number of graduates have experience
Total graduates to have experience = 60
2) For minimum number of graduates have experience
Remaining after taking other than graduates in experience= 80-75 = 5
Ratio of fruits (by dozen) = 3:2:7
Ratio of fruits (by weight) = 120 :150: 24
Therefore, Ratio of fruits (combined) by weight = 3 x 120 : 2 x 150 : 7 x 24 = 30 : 25 : 14
Angle of triangle = 180 × 3/12
= 45 deg
Other angles of the triangle are = 60 deg, 75 deg
Angle of quadrilateral
= 360 - (45 + 60 + 75)
= 180 deg
Therefore, the four angles of the quadrilateral are 45, 60, 75 & 180 degrees.
Hence, the sum of largest and smallest angle of the quadrilateral are 180 + 45 = 225 deg.
To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres.
=> the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres
However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity.
i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too.
Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.
Let the quantity of alcohol and water be 4x liters and 3x liters respectively. Then,
(4x)/(3x+5) = 4/5
=> 20x = 4(3x+5)
=> x = 2.5
Quantity of alcohol = (4 * 2.5) liters = 10 liters.
A B C
3x 4x 5x
(3x+x) 2x (5x+x) (B Gives 1/4 to A and 1/4 to C)
=4x 2x 6x
(4x+x) 2x 5x ( C Gives 1/6 to A)
=5x 2x 5x
Therefore, 5 : 2 : 5
Maximum earning will be only when he will won on the maximum yielding table.
A ----> 10:1
B ----> 20:1
C ----> 30:1
i.e, he won on B and C but lost on A
20 x 200 + 30 x 200 -1 x 200 = 9800
minimum earning will be when he won on table A and B and lose on that table 3.
Therefore, 10 x 200 + 20 x 200 - 1 x 200 = 6000-200 = 5800
Therefore, Difference= 9800 - 5800 = 4000
Given 5:6 :: 7:10 :: 6:5
We know that compound ratio is calculated as
a:b :: c:d :: e:f
(axcxe):(bxdxf)
=> (5x7x6):(6x10x5)
=> (210):(300)
= 7:10
4:5
3:2
-------
=> 12:15:10
12:10
=> 6:5
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