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- Question
A and B invests Rs.8000 and Rs.9000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year ?
Options- A. 21:29
- B. 41:54
- C. 32:45
- D. 37:51
- Correct Answer
- 32:45
ExplanationA : B
(8000x4)+(4000x8) : (9000x6)+(6000x6)
64000 : 90000
=> 32 : 45 - 1. A man spend Rs. 810 in buying trouser at Rs. 70 each and shirt at Rs. 30 each. What will be the ratio of trouser and shirt when the maximum number of trouser is purchased ?
Options- A. 1:3
- B. 2:1
- C. 3:2
- D. 2:3 Discuss
- 2. The ratio of students in a coaching preparing for B.tech and MBA is 4 : 5. The ratio of fees collected from each of B.tech and MBA students is 25 : 16. If the total amount collected from all the students is 1.62 lakh, what is the total amount collected from omly MBA aspirants?
Options- A. Rs. 62,000
- B. Rs. 72,000
- C. Rs. 82,000
- D. None of these Discuss
- 3. 64 boys and 40 girls form a group for social work. During their membership drive, the same number of boys and girls joined the group. How many members does the group have now, if the ratio of boys to girls is 4:3 ?
Options- A. 168
- B. 201
- C. 147
- D. 154 Discuss
- 4. Two solutions have milk & water in the ratio 7:5 and 6:11. Find the proportion in which these two solutions should Be mixed so that the resulting solution has 1 part milk and 2 parts water ?
Options- A. 7 : 12
- B. 8 : 13
- C. 9 : 4
- D. 2 : 5 Discuss
- 5. There are two containers, the first one contains 1 litre pure water and the second one contains 1 litre pure milk.Now 5 cups of water from the first container is taken out is mixed well in the second container. Then, 5 cups of this mixture is taken out and is mixed in the first container. Let A denote the proportion of milk in the first container and B denote the proportion of water in the second container then:
Options- A. A
- B. A=B
- C. A>B
- D. can't be determined Discuss
- 6. In a fort, there are 1200 soldiers. If each soldier consumes 3 kg per day, the provisions available in the fort will last for 30 days. If some more soldiers join, the provisions available will last for 25 days given each soldier consumes 2.5 kg per day. Find the number of soldiers joining the fort in that case ?
Options- A. 693
- B. 741
- C. 528
- D. 654 Discuss
- 7. If 6 men and 3 boys working together, can do four times as much work per hour as a man and a boy together. Find the ratio of the work done by a man and that of a boy for a given time ?
Options- A. 1 : 2
- B. 2 : 1
- C. 3 : 1
- D. 1 : 3 Discuss
- 8. The sum of three numbers is 98. If the ratio of the first to the second is 2:3. And that of the second to the third is 5:8, then the second number is:
Options- A. 10
- B. 15
- C. 20
- D. 30 Discuss
- 9. 80 litres of diesel is required to travel 800 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 1000 kms using 1200 cc engine ?
Options- A. 120 lit
- B. 140 lit
- C. 110 lit
- D. 150 lit Discuss
- 10. The ratio of the angles of a triangle is 3 : 4 : 5. The three angles of a quadrilateral is equal to three angles of this triangle. What is the sum of the largest angle and second smallest angle of the quadrilateral ?
Options- A. 225 deg
- B. 210 deg
- C. 205 deg
- D. 245 deg Discuss
Ratio and Proportion problems
Search Results
Correct Answer: 3:2
Explanation:
Let us assume S as number of shirts and T as number of trousers
Given that each trouser cost = Rs.70 and that of shirt = Rs.30
Therefore, 70 T + 30 S = 810
=> 7T + 3S = 81......(1)
T = ( 81 - 3S )/7
We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of T
Simplifying by taking 3 as common factor i.e, 3(27-S) / 7
In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7
Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9
Hence for S, put T in eq(1), we get
S = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.
The ratio of T:S = 9:6 = 3:2.
Correct Answer: Rs. 72,000
Explanation:
The ratio of fees collected from B.Tech : MBA = 4x * 25y : 5x * 16y
= 100xy : 80xy
= 5xy : 4 xy = 5k : 4k
The amount collected only from MBA students = = Rs. 72,000
Correct Answer: 168
Explanation:
Let us say x boys and x girls joined the group.
(64 + x)/(40 + x) = 4/3
192 + 3x = 160 + 4x => x = 32
Number of members in the group = 64 + x + 40 + x
= 104 + 2x = 168.
Correct Answer: 8 : 13
Explanation:
To get the solution that contains 1 part of milk and two parts of water,
they must be mixed in the ratio as
7x+6x/5y+11y = 1/2
26x = 16y
x/y = 16/26
x/y = 8/13
Correct Answer: A=B
Explanation:
Here the ratio of mixtures( i.e milk , water) doesnot matter. But the important point is that whether the total amount ( either pure or mixture ) being transferred is equal or not.Since the total amount ( i.e 5 cups) being transferred from each one to another , hence A =B.
Correct Answer: 528
Explanation:
Assume x soldiers join the fort. 1200 soldiers have provision for 1200 (days for which provisions last them)(rate of consumption of each soldier)
= (1200)(30)(3) kg.
Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) k
As the same provisions are available
=> (1200)(30)(3) = (1200 + x)(25)(2.5)
x = ([(1200)(30)(3)] / (25)(2.5)) - 1200 => x = 528.
Correct Answer: 1 : 2
Explanation:
6M + 3B = 4(1M + 1B)
6M + 3B = 4M + 4B
2M = 1B
M/B = 1/2
Correct Answer: 30
Explanation:
Let the three parts M, N, O.
Then, M:N = 2:3 and N:O = 5:8
= (5 x 3/5) : (8 x 3/5) = 3:24/5
M:N:O = 2:3:24/5
= 10:15:24 => N = 98 x 15/49 = 30.
Correct Answer: 150 lit
Explanation:
To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres.
=> the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres
However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity.
i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too.
Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.
Correct Answer: 225 deg
Explanation:
Angle of triangle = 180 × 3/12
= 45 deg
Other angles of the triangle are = 60 deg, 75 deg
Angle of quadrilateral
= 360 - (45 + 60 + 75)
= 180 deg
Therefore, the four angles of the quadrilateral are 45, 60, 75 & 180 degrees.
Hence, the sum of largest and smallest angle of the quadrilateral are 180 + 45 = 225 deg.
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