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- Question
Two numbers are in the ratio 3 : 7. If 6 be added to each of them, then they are in the ratio 5 : 9. Find the numbers ?
Options- A. 11 & 17
- B. 7 & 17
- C. 9 & 21
- D. 13 & 23
- Correct Answer
- 9 & 21
ExplanationLet the two numbers be x and y
Given x : y = 3 : 7 .....(1)
Now, x+6 : y+6 = 5 : 9 .....(2)
From (1), x = 3y/7
From (2), 5y - 9x = 24
=> 5y - 9(3y/7) = 24
=> y = 21
=> From(1), x = 9
Hence, the two numbers be 9 and 21
- 1. The ratio of Pens and Pencils in a shop is 3 : 2 respectively. The average number of Pens and Pencils is 180. What is the number of Pencils in the shop?
Options- A. 444
- B. 344
- C. 244
- D. 144 Discuss
- 2. A child has three different kinds of chocolates costing Rs.2, Rs.5, Rs.10. He spends total Rs. 120 on the chocolates. what is the minimum possible number of chocolates he can buy, if there must be atleast one chocolate of each kind?
Options- A. 22
- B. 19
- C. 17
- D. 15 Discuss
- 3. Three cats are roaming in a zoo n such a way that when cat A takes 5 steps, B takes 6 steps and C takes 7 steps.But the 6 steps of A are equal to the 7 steps of B and 8 steps of C. what is the ratio of their speeds?
Options- A. 140:144:147
- B. 40:44:47
- C. 15:21:28
- D. 252:245:240 Discuss
- 4. The ratio of the incomes of Pavan and Amar is 4 : 3 and the ratio of their expenditures are 3:2. If each person saves Rs. 1889, then find the income of Pavan?
Options- A. 6548
- B. 5667
- C. 7556
- D. 8457 Discuss
- 5. If the ratio of the ages of two friends A and B is in the ratio 3 : 5 and that of B and C is 3 : 5 and the sum of their ages is 147, then how old is B?
Options- A. 27 Years
- B. 75 Years
- C. 45 Years
- D. 49 Years Discuss
- 6. Vinod have 20 rupees. He bought 1, 2, 5 rupee stamps. They are different in numbers by the reason of no change, the shop keeper gives 3 one rupee stamps. So how many stamps Vinod have ?
Options- A. 10
- B. 18
- C. 12
- D. 15 Discuss
- 7. The incomes of two persons A and B are in the ratio 3 : 4. If each saves Rs.100 per month, the ratio of their expenditures is Rs. 1 : 2. Find their incomes.
Options- A. Rs. 100 and Rs.150
- B. Rs. 150 and Rs.200
- C. Rs.200 and Rs.250
- D. Rs.250 and Rs.300 Discuss
- 8. In a competitive exam, the number of passed students was four times the number of failed students. If there had been 35 fewer appeared students and 9 more had failed, the ratio of passed and failed students would have been 2 : 1, then the total number of students appered for the exam ?
Options- A. 175
- B. 165
- C. 155
- D. 145 Discuss
- 9. There is certain numbers of toys in the box. They are divided into such a way that the person who gets 1/4 of the whole gets thrice of what the others get on an average. Find the number of people amongst whom the toys are distributed?
Options- A. 8
- B. 10
- C. 12
- D. 9 Discuss
- 10. 16 : 56 :: 32 : ?
Options- A. 196
- B. 148
- C. 132
- D. 112 Discuss
Ratio and Proportion problems
Search Results
Correct Answer: 144
Explanation:
Given ratio of pens and pencils = 3 :2
Number of Pens = 3x
Number of Pencils = 2x
Average number of pencils & Pens = 180
5x = 360
=> x = 72
Hence, the number of pencils = 2x = 72 x 2 = 144.
Correct Answer: 17
Explanation:
Minimum number of chocolates are possible when he purchases maximum number of costliest chocolates.
Thus, 2 x 5 + 5 x 2 =Rs.20
Now Rs.100 must be spend on 10 chocolates as 100 = 10 x 10.
Thus minumum number of chocolates = 5 + 2 + 10 = 17
Correct Answer: 140:144:147
Explanation:
Frequency of step of A:B:C = 5 : 6 : 7
But in terms of size of step, 6A = 7B = 8C
Therefore, Ratio of speeds of A, B and C = 5/6 : 6/7 : 7/8 = 140 : 144 : 147
Correct Answer: 7556
Explanation:
Let ratio of the incomes of Pavan and Amar be 4x and 3x
and Ratio of their expenditures be 3y and 2y
4x - 3y = 1889 ......... I
and
3x - 2y = 1889 ...........II
I and II
y = 1889
and x = 1889
Pavan's income = 7556
Correct Answer: 45 Years
Explanation:
The ratio of the ages of A and B is 3 : 5.
The ratio of the ages of B and C is 3 : 5.
B's age is the common link to both these ratio. Therefore, if we make the numerical value of the ratio of B's age in both the ratios same, then we can compare the ages of all 3 in a single ratio.
The can be done by getting the value of B in both ratios to be the LCM of 3 and 5 i.e., 15.
The first ratio between A and B will therefore be 9 : 15 and
the second ratio between B and C will be 15 : 25.
Now combining the two ratios, we get A : B : C = 9 : 15 : 25.
Let their ages be 9x, 15x and 25x.
Then, the sum of their ages will be 9x + 15x + 25x = 49x
The question states that the sum of their ages is 147.
i.e., 49x = 147 or x = 3.
Therefore, B's age = 15x = 15*3 = 45
Correct Answer: 10
Explanation:
Given total rupees = 20 Rs
No. of one rupee stamps = 3
Now, remaining money = Rs. 17
With that he buys only 2 and 5 rupee stamps
Let number of Rs. 5 stamps = K
Let number of Rs. 2 stamps = L
5K + 2L = 17
K = 3, L = 1 (possible)
L = 6, K = 1 (possible)
=> But given that they are different in number so, K is not equal to 3
one rupee stamps = 3
2 two stamps = 6
5 rupee stamps = 1
Total number of stamps = 10.
Correct Answer: Rs. 150 and Rs.200
Explanation:
Let the incomes of A and B be 3P and 4P.
If each saves Rs. 100 per month, then their expenditures = Income - savings = (3P - 100) and (4P - 100).
The ratio of their expenditures is given as 1 : 2.
Therefor, (3P - 100) : (4P - 100) = 1 : 2
Solving, We get P = 50. Substitute this value of P in 3P and 4P.
Thus, their incomes are : Rs.150 and Rs.200
Correct Answer: 155
Explanation:
Let the number of failed students be x
=> Number of passed students = 4x
So total number of students was 5x
From the given data,
If total number of students be 5x ? 35
=> 4x-35-9/x+9 = 2/1
=> 4x ? 44 = 2(x + 9)
=> 4x ? 2x = 18 + 44
=> x = 31
Total number = 31×5
= 155
Correct Answer: 10
Explanation:
If the person who gets 1/4 of the whole gets thrice of what the others get on an average, each one will get =1/3×1/4=112 of the whole.
Therefore, if there are k persons other than the person who gets one-fourth, then 1/4 + k/12 = 1
? k=9
Hence, total number of people = 10.
Correct Answer: 112
Explanation:
16 : 56 :: 32 : ?
Let the required number be 'n'
The given numbers follow a logic that,
16/56 = 2/7
=> 32/n = 2/7
=> 32 x 7/2 = n
=> n = 112.
Hence, 16 : 56 :: 32 : 112.
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