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- Question
Three cats are roaming in a zoo n such a way that when cat A takes 5 steps, B takes 6 steps and C takes 7 steps.But the 6 steps of A are equal to the 7 steps of B and 8 steps of C. what is the ratio of their speeds?
Options- A. 140:144:147
- B. 40:44:47
- C. 15:21:28
- D. 252:245:240
- Correct Answer
- 140:144:147
ExplanationFrequency of step of A:B:C = 5 : 6 : 7
But in terms of size of step, 6A = 7B = 8C
Therefore, Ratio of speeds of A, B and C = 5/6 : 6/7 : 7/8 = 140 : 144 : 147
- 1. The ratio of the incomes of Pavan and Amar is 4 : 3 and the ratio of their expenditures are 3:2. If each person saves Rs. 1889, then find the income of Pavan?
Options- A. 6548
- B. 5667
- C. 7556
- D. 8457 Discuss
- 2. If the ratio of the ages of two friends A and B is in the ratio 3 : 5 and that of B and C is 3 : 5 and the sum of their ages is 147, then how old is B?
Options- A. 27 Years
- B. 75 Years
- C. 45 Years
- D. 49 Years Discuss
- 3. Rice worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, then the price of third variety of rice per kg?
Options- A. Rs. 571.25
- B. Rs. 175.5
- C. Rs. 751.75
- D. Rs. 850 Discuss
- 4. A cubical block of metal weighs 6 pounds. How much will another cube of the same metal weigh if its sides are twice as long?
Options- A. 48
- B. 12
- C. 36
- D. 60 Discuss
- 5. For any two numbers m , n ; (m+n) : (m-n) : mn = 7: 1: 60 . Find the value of 1/m : 1/n
Options- A. 4:3
- B. 8:7
- C. 3:4
- D. 7:8 Discuss
- 6. A child has three different kinds of chocolates costing Rs.2, Rs.5, Rs.10. He spends total Rs. 120 on the chocolates. what is the minimum possible number of chocolates he can buy, if there must be atleast one chocolate of each kind?
Options- A. 22
- B. 19
- C. 17
- D. 15 Discuss
- 7. The ratio of Pens and Pencils in a shop is 3 : 2 respectively. The average number of Pens and Pencils is 180. What is the number of Pencils in the shop?
Options- A. 444
- B. 344
- C. 244
- D. 144 Discuss
- 8. Two numbers are in the ratio 3 : 7. If 6 be added to each of them, then they are in the ratio 5 : 9. Find the numbers ?
Options- A. 11 & 17
- B. 7 & 17
- C. 9 & 21
- D. 13 & 23 Discuss
- 9. Vinod have 20 rupees. He bought 1, 2, 5 rupee stamps. They are different in numbers by the reason of no change, the shop keeper gives 3 one rupee stamps. So how many stamps Vinod have ?
Options- A. 10
- B. 18
- C. 12
- D. 15 Discuss
- 10. The incomes of two persons A and B are in the ratio 3 : 4. If each saves Rs.100 per month, the ratio of their expenditures is Rs. 1 : 2. Find their incomes.
Options- A. Rs. 100 and Rs.150
- B. Rs. 150 and Rs.200
- C. Rs.200 and Rs.250
- D. Rs.250 and Rs.300 Discuss
Ratio and Proportion problems
Search Results
Correct Answer: 7556
Explanation:
Let ratio of the incomes of Pavan and Amar be 4x and 3x
and Ratio of their expenditures be 3y and 2y
4x - 3y = 1889 ......... I
and
3x - 2y = 1889 ...........II
I and II
y = 1889
and x = 1889
Pavan's income = 7556
Correct Answer: 45 Years
Explanation:
The ratio of the ages of A and B is 3 : 5.
The ratio of the ages of B and C is 3 : 5.
B's age is the common link to both these ratio. Therefore, if we make the numerical value of the ratio of B's age in both the ratios same, then we can compare the ages of all 3 in a single ratio.
The can be done by getting the value of B in both ratios to be the LCM of 3 and 5 i.e., 15.
The first ratio between A and B will therefore be 9 : 15 and
the second ratio between B and C will be 15 : 25.
Now combining the two ratios, we get A : B : C = 9 : 15 : 25.
Let their ages be 9x, 15x and 25x.
Then, the sum of their ages will be 9x + 15x + 25x = 49x
The question states that the sum of their ages is 147.
i.e., 49x = 147 or x = 3.
Therefore, B's age = 15x = 15*3 = 45
Correct Answer: Rs. 175.5
Explanation:
Let the price of required variety = Rs. P/kg
Then, respective amounts were m kg, m kg and 2m kg
= 126m + 135m + 2pm = 153 x 4m
=> 2p = 351
p = 175.5 / kg
Correct Answer: 48
Explanation:
If you double the sides of a cube, the ratio of the surface areas of the old and new cubes will be 1: 4. The ratio of the volumes of the old and new cubes will be 1: 8.
Weight is proportional to volume. So, If the first weighs 6 pounds, the second weighs 6x8 pounds =48.
Correct Answer: 3:4
Explanation:
Again
and mn =60x
so,
=> m= 20 and n= 15
Hence,
Correct Answer: 17
Explanation:
Minimum number of chocolates are possible when he purchases maximum number of costliest chocolates.
Thus, 2 x 5 + 5 x 2 =Rs.20
Now Rs.100 must be spend on 10 chocolates as 100 = 10 x 10.
Thus minumum number of chocolates = 5 + 2 + 10 = 17
Correct Answer: 144
Explanation:
Given ratio of pens and pencils = 3 :2
Number of Pens = 3x
Number of Pencils = 2x
Average number of pencils & Pens = 180
5x = 360
=> x = 72
Hence, the number of pencils = 2x = 72 x 2 = 144.
Correct Answer: 9 & 21
Explanation:
Let the two numbers be x and y
Given x : y = 3 : 7 .....(1)
Now, x+6 : y+6 = 5 : 9 .....(2)
From (1), x = 3y/7
From (2), 5y - 9x = 24
=> 5y - 9(3y/7) = 24
=> y = 21
=> From(1), x = 9
Hence, the two numbers be 9 and 21
Correct Answer: 10
Explanation:
Given total rupees = 20 Rs
No. of one rupee stamps = 3
Now, remaining money = Rs. 17
With that he buys only 2 and 5 rupee stamps
Let number of Rs. 5 stamps = K
Let number of Rs. 2 stamps = L
5K + 2L = 17
K = 3, L = 1 (possible)
L = 6, K = 1 (possible)
=> But given that they are different in number so, K is not equal to 3
one rupee stamps = 3
2 two stamps = 6
5 rupee stamps = 1
Total number of stamps = 10.
Correct Answer: Rs. 150 and Rs.200
Explanation:
Let the incomes of A and B be 3P and 4P.
If each saves Rs. 100 per month, then their expenditures = Income - savings = (3P - 100) and (4P - 100).
The ratio of their expenditures is given as 1 : 2.
Therefor, (3P - 100) : (4P - 100) = 1 : 2
Solving, We get P = 50. Substitute this value of P in 3P and 4P.
Thus, their incomes are : Rs.150 and Rs.200
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