If you double the sides of a cube, the ratio of the surface areas of the old and new cubes will be 1: 4. The ratio of the volumes of the old and new cubes will be 1: 8.
Weight is proportional to volume. So, If the first weighs 6 pounds, the second weighs 6x8 pounds =48.
Again
and mn =60x
so,
=> m= 20 and n= 15
Hence,
Let the salaries of Maneela and Shanthi one year before be M1, S1 & now be M2, S2 respectively.
Then, from the given data,
M1/S1 = 3/4 .....(1)
M1/M2 = 4/5 .....(2)
S1/S2 = 2/3 .....(3)
and M2 + S2 = 4160 .....(4)
Solving all these eqtns, we get M2 = Rs. 1600.
The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs 5000 ?
Ratio of increase of wages = 22:25
Ratio of decrease of labourers = 15:11
Compound ratio of wages of labourers = 22 x 15 : 25 x 11 = 330:275
Final bill = Rs. 5000
For 275 ratio wages = Rs. 5000
For 1 ratio wages = 5000/275
For 330 ratio wages = 5000/275 x 330 = Rs. 6000
Let the price of required variety = Rs. P/kg
Then, respective amounts were m kg, m kg and 2m kg
= 126m + 135m + 2pm = 153 x 4m
=> 2p = 351
p = 175.5 / kg
The ratio of the ages of A and B is 3 : 5.
The ratio of the ages of B and C is 3 : 5.
B's age is the common link to both these ratio. Therefore, if we make the numerical value of the ratio of B's age in both the ratios same, then we can compare the ages of all 3 in a single ratio.
The can be done by getting the value of B in both ratios to be the LCM of 3 and 5 i.e., 15.
The first ratio between A and B will therefore be 9 : 15 and
the second ratio between B and C will be 15 : 25.
Now combining the two ratios, we get A : B : C = 9 : 15 : 25.
Let their ages be 9x, 15x and 25x.
Then, the sum of their ages will be 9x + 15x + 25x = 49x
The question states that the sum of their ages is 147.
i.e., 49x = 147 or x = 3.
Therefore, B's age = 15x = 15*3 = 45
Let ratio of the incomes of Pavan and Amar be 4x and 3x
and Ratio of their expenditures be 3y and 2y
4x - 3y = 1889 ......... I
and
3x - 2y = 1889 ...........II
I and II
y = 1889
and x = 1889
Pavan's income = 7556
Frequency of step of A:B:C = 5 : 6 : 7
But in terms of size of step, 6A = 7B = 8C
Therefore, Ratio of speeds of A, B and C = 5/6 : 6/7 : 7/8 = 140 : 144 : 147
Minimum number of chocolates are possible when he purchases maximum number of costliest chocolates.
Thus, 2 x 5 + 5 x 2 =Rs.20
Now Rs.100 must be spend on 10 chocolates as 100 = 10 x 10.
Thus minumum number of chocolates = 5 + 2 + 10 = 17
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