Let the salaries of A, B, C be x, 2x and 3x respectively.
Then,2x + 3x = 6000 => x = 1200.
A's salary = Rs. 1200, B's salary = Rs. 2400, and Cs salary Rs. 3600.
Excess of C's salary over A's=[ (2400 /1200) x 100] = 200%.
Let the third proportion to 9 & 12 be 'x'.
=> 9:12 = 12 :p
=> p = 12x12/9 = 16.
Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively.
Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x).
? [(140/100) × 5x],[(150/100) × 7x] and [(175/100) × 8x]
? 7x, 21x/2 and 14x.
? The required ratio =7x : 21x/2 : 14x
? 14x : 21x : 28x
? 2 : 3 : 4
Suppose there are all the pigeons then total no of heads are 340 and total no of legs are 680.
Now, since 380 (1060-680) legs are extra, it means there will be 190 (380/2) rabbits.As we know a rabbit has two extra legs than that of a pigeon.
Therefore, number of rabbits =190
and number of pigeons = 340- 190 = 150
3A = 4B = 7C = k,Then A = k/3, B = k/4 and C= k/7.
A : B : C = k/3 : k/4 : k/7 = 28:21 :12.
Cs share = Rs. [427 x (12/61)] = Rs. 84
(x * 5) = (0.75 *8)
X=6/5 = 1.20
Dog : Hare = (3*3) leaps of hare : 5 leaps of hare = 9 : 5.
Let the number of boys and girls be 8x and 5x.
Total number of students = 13x = 13 * 32 = 416.
Concentration of petrol in A B C
1/2 3/5 4/5
Quantity of petrol taken from A = 1 litre out of 2 litre
Quantity of petrol taken from B = 1.8litre out of 3 litre
Quantity of petrol taken from C = 0.8 litre out of 1 litre
Therefore, total petrol taken out from A, B and C = 1+1.8+0.8 =3.6 litres
So, the quantity of kerosen =(2+3+1) - 3.6 =2.4 litre
Thus, the ratio of petrol to kerosene = 3.6/2.4 = 3/2
Assume the weight of alloy a is 100 kg
Therefore, The weight of alloy B is 400kg
Gold silver copper
A 40kg 60kg 0kg
B 140kg 160kg 100kg
total 180kg 220kg 100kg
Therefore, Ratio of gold and silver in new alloy = = 36% :44%
Let, B1 : B2 : B3 = 3x : 4x : 5x
again B1 : B2 : B3 = 5y : 4y : 3y
Since there is increase in no.of oranges in first two baskets only, it means the no. of oranges remains constant in the third basket
Therefore, 5x = 3y
Hence 3x : 4x : 5x => = 9y:12y:15y
and 5y : 4y : 3y => 25x : 20x : 15x
Therfore, increment in first basket = 16
Increment in second basket = 8
Thus, required ratio = 16/8 = 2:1
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