B runs 35 m in 7 sec.
B covers 200 m in (7/35*200) = 40sec
B's time over the course = 40 sec.
A's time over the course (40 - 7) sec = 33 sec.
A : B = 100 : 90.
A : C = 100 : 72.
B:C = B/A*A/C = 90/100*100/72 = 90/72
When B runs 90 m, C runs 72 m.
When B runs 100 m, C runs (72/90*100)m = 80m
B can give C 20 m.
let ratio be x.
Hence no. of coins be 5x ,9x , 4x respectively
Now given total amount = Rs.206
=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206
we get x = 40
=> No. of 50p coins = 200
=> No. of 25p coins = 360
=> No. of 10p coins = 160
Let the third number be x.
Then, first number = 120% of x =120x/100 = 6x/5
Second number =150% of x = 150x/100 = 3x/2
Ratio of first two numbers = 6x/5 : 3x/2 = 12x : 15x = 4 : 5
Let the quantity of alcohol and water be 4x litres and 3x litres respectively
4x/(3x+5) = 4/5
20x = 4(3x+5)
8x = 20
x = 2.5
Quantity of alcohol = (4 x 2.5) litres = 10 litres.
Given ratio = = 6:8:9
1st part = = Rs. 204
Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.
Then,
(2x+4000) / (3x+4000) = 40 / 57
? 57 × (2x + 4000) = 40 × (3x+4000)
? 6x = 68,000
? 3x = 34,000
Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38,000
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