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- Question
At a game of billiards, A can give B 15 points in 60 and A can give C to 20 points in 60. How many points can B give C in a game of 90?
Options- A. 30 points
- B. 20 points
- C. 10 points
- D. 12 points
- Correct Answer
- 10 points
- 1. A can run 22.5 m while B runs 25 m. In a kilometre race B beats A by
Options- A. 100 m
- B. 111m
- C. 25 m
- D. 50 m Discuss
- 2. In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by
Options- A. 5.4 m
- B. 4.5 m
- C. 5 m
- D. 6 m Discuss
- 3. In a 200 metres race A beats B by 35 m or 7 seconds. A's time over the course is:
Options- A. 40 sec
- B. 47 sec
- C. 33 sec
- D. None of these Discuss
- 4. In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:
Options- A. 18 m
- B. 20 m
- C. 27m
- D. 9 m Discuss
- 5. In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C:
Options- A. 8 points
- B. 10 points
- C. 14points
- D. 40points Discuss
- 6. In 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by
Options- A. 20 m
- B. 25 m
- C. 22.5 m
- D. 9 m Discuss
- 7. A bag contains 50 P, 25 P and 10 P coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type respectively.
Options- A. 360, 160, 200
- B. 160, 360, 200
- C. 200, 360,160
- D. 200,160,300 Discuss
- 8. Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
Options- A. 2:5
- B. 3:5
- C. 4:5
- D. 5:4 Discuss
- 9. A mixture contains alcohol and water in the ratio 4 : 3. If 5 liters of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture.
Options- A. 10
- B. 12
- C. 15
- D. 18 Discuss
- 10. If Rs. 782 be divided into three parts, proportional to 12:23:34 , then the first part is?
Options- A. Rs. 182
- B. Rs. 190
- C. Rs. 192
- D. Rs. 204 Discuss
Races and Games problems
Search Results
Correct Answer: 100 m
Correct Answer: 6 m
Correct Answer: 33 sec
Explanation:
B runs 35 m in 7 sec.
B covers 200 m in (7/35*200) = 40sec
B's time over the course = 40 sec.
A's time over the course (40 - 7) sec = 33 sec.
Correct Answer: 20 m
Explanation:
A : B = 100 : 90.
A : C = 100 : 72.
B:C = B/A*A/C = 90/100*100/72 = 90/72
When B runs 90 m, C runs 72 m.
When B runs 100 m, C runs (72/90*100)m = 80m
B can give C 20 m.
Correct Answer: 10 points
Explanation:
A : B = 100 : 80.
A : C = 100 : 72.
B:C = B/A*A/C = 80/10*100/72 = 10/9 = 100/90 = 100:90
B can give C 10 points
Correct Answer: 20 m
Correct Answer: 200, 360,160
Explanation:
let ratio be x.
Hence no. of coins be 5x ,9x , 4x respectively
Now given total amount = Rs.206
=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206
we get x = 40
=> No. of 50p coins = 200
=> No. of 25p coins = 360
=> No. of 10p coins = 160
Correct Answer: 4:5
Explanation:
Let the third number be x.
Then, first number = 120% of x =120x/100 = 6x/5
Second number =150% of x = 150x/100 = 3x/2
Ratio of first two numbers = 6x/5 : 3x/2 = 12x : 15x = 4 : 5
Correct Answer: 10
Explanation:
Let the quantity of alcohol and water be 4x litres and 3x litres respectively
4x/(3x+5) = 4/5
20x = 4(3x+5)
8x = 20
x = 2.5
Quantity of alcohol = (4 x 2.5) litres = 10 litres.
Correct Answer: Rs. 204
Explanation:
Given ratio = = 6:8:9
1st part = = Rs. 204
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