Given,Let the cost price of single book be Rs. 100.
The cost price of (9 + 1) = 10 pair i.e. 20 books = Rs. (100 × 20) = Rs. 2000.He gets profit of 26%.
So, the selling price of 9 pair i.e. 18 books = Rs. 2000 × (126/100) = Rs. 2520
Then,the selling price of single book = Rs. 2520/18 = Rs. 140
He gives 20% discount on the marked price of a book.
That means, when the selling price is Rs. 80 then the marked price is Rs. 100.
?When the selling price of single book is Rs. 140, the marked price = Rs. 140 × (100/80) = Rs. 175
?The percentage increase in marked price from the cost price = (175 ?100)% = 75%
SP of each car is Rs. 404415, he gains 15% on first car and losses 15% on second car.
% Profit with respect to A = 40 + 50 + (40 x 50)/100 = 90 + 20 = 110 %.
C.P of article = 6500 * (100/80) = Rs. 8125 S.P for a gain of 20% = (8125*120)/100 = Rs. 9750
Let cost price of each bread packet = a Rs.
So, marked price of each bread packet = 2.5a
And selling price of each bread packet = 2.5a × 60/100 = 1.5a
Given, 1.5a ?
Let the cost price of A as well as B is 100 Rs.
Then, ATQ:
Selling Price of A = 100+40 = 140
And Selling Price of B = 140 - (140*0.2) = 140 - 28 = 112
Total selling price = 140+112 = 252 Rs.
Total Cost price = Rs. 200
So by taking cost price = 100 Rs.
Total profit = 52 Rs.
Total profit will be Rs. 156 when cost price = (100/52)*156 = Rs. 300.
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