Let the C.P be 'x'
Then, the selling price S.P = x - 16x/100
= 84x/100 = 21x/25
Now, if the S.P is 60 more, then the profit is 14%
=> 21x/25 + 60 = x + 14x/100
=> 114x/100 - 21x/25 = 60
=> (57 - 42)x/50 = 60
=> 15x/50 = 60
x = 3000/15 = 200
Therefore, the Cost price C.P = x = Rs. 200
Profit would be maximum if watches are brought for Rs. 200 and sold for Rs. 425
Profit = Rs. (425 - 200) = Rs. 225
Profit of 9 watches = Rs. 225 x 9 = Rs.2,025.
C.P. of 50 kg rice = Rs. (36 x 20 + 14 x 36) = Rs. (720 + 504) = Rs.1224.
S.P. of 56 kg rice = Rs. (50 x 30) = Rs.1500.
Profit = 1500 - 1224 = Rs.276
Profit % = = = 22.54%.
Initial amount spent on trouser by the man = Rs. 1250
Now, by the reduction of 20% in 1250, he can buy t-shirt too.
=> t-shirt cost = 20% of 1250 = 20 x 1250/100 = 250
Therefore, the price of the t-shirt = Rs. 250.
The first lost Rs. 100, but after the thief bought Rs. 60 goods, he get that Rs. 100 back but he lost Rs. 60 value of goods and Rs. 40 in change.
So, a total of 60 + 40 = 100 Rs. the owner lose.
CP of 1000gm = Rs. 10
SP of 800gm = Rs. 12
SP of 1000gm =12x1000/800 = Rs. 15
Now take 1000gm as reference to calculate profit.
Profit=SP-CP=15-10=Rs. 5
Profit % = 5x100/10 = 50%
Let the selling price for each of the shopkeeper be Rs 100x
For 1st shopkeeper
SP= Rs 100x
CP=100
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