Let the cost price of a ball is Rs.x
Given, on selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls
The equation is :
17x - 720 = 5x
Solving the equation
we get x = 60
Therefore, cost price of a ball is Rs. 60.
loss % = %
= (20/10)x(20/10)% = 4%
Total cost of all varieties of mangoes = 20 x 2 + 40 x 3 + 50 x 5 = 40 + 120 + 250 = Rs. 410
Then, cost of 1 kg mangoes = 410/10 = Rs. 41
To get 20% profit,
The rate at which the mangoes should be sell = 120/100 x 41 = Rs. 49.2
When 3 passengers income was 3x
expense= Rs.30
profit =20% of 30 = Rs.6
That means his earning is Rs.36. so that per passenger fare must be Rs.12.
When 4 passengers
earning = 12x4=Rs.48.
expense =Rs.24.
profit = Rs.24 = 100%
Let 1kg of Rs. 100 then 840gm is of Rs. 84.
Now (label on can 1kg but contains 840kg ) so for customer it is of Rs. 100 and further gives 4% discount [he sells his article on 4% loss on cost price.]
So now S.P = Rs. 96
But actually it contains 840 gm so C.P for shopkeeper = Rs. 84
S.P = Rs. 96
C.P = Rs. 84
Profit% = {(S.P-C.P)/C.P}x100
{(96-84)/84} x 100 = 14.28571429% PROFIT.
Let the Cost price of the powerbank = Rs. P
But given that by selling it at Rs. 1950, it gives a loss of 25%
=>
=>
= Rs. 2600
Now, to get a profit of 25%
Selling Price = .
Let C1 be the cost price of the first article and C2 be the cost price of the second article.
Let the first article be sold at a profit of 22%, while the second one be sold at a loss of 8%.
We know, C1 + C2 = 600.
The first article was sold at a profit of 22%. Therefore, the selling price of the first article = C1 + (22/100)C1 = 1.22C1
The second article was sold at a loss of 8%. Therefore, the selling price of the second article = C2 - (8/100)C2 = 0.92C2.
The total selling price of the first and second article = 1.22C1 + 0.92C2.
As the merchant did not make any profit or loss in the entire transaction, his combined selling price of article 1 and 2 is the same as the cost price of article 1 and 2.
Therefore, 1.22C1 + 0.92C2 = C1+C2 = 600
As C1 + C2 = 600, C2 = 600 - C1. Substituting this in 1.22C1 + 0.92C2 = 600, we get
1.22C1 + 0.92(600 - C1) = 600
or 1.22C1 - 0.92C1 = 600 - 0.92*600
or 0.3C1 = 0.08*600 = 48
or C1 = 48/(0.3) = 160.
If C1 = 160, then C2 = 600 - 160 = 440.
The item that is sold at loss is article 2. The selling price of article 2 = 0.92*C2 = 0.92*440 = 404.80.
Let the cost price of the fruits be 'C.P'
From the given data, after analysis it can be solved as
(121% of C.P) - (125% of 91% of C.P) = 29
Hence, the cost price of the fruits = Rs. 400.
Cost price = Rs. 30
Selling price = Rs. 50
Gain = Rs. 20
Profit % = Gain/cost price x 100 = 20/50 x 100 = 40%
Let the profit be Rs. p
Then Cost price of the bag = 340p/100 = 3.4p
According to question,
3.4p + p = 1540
4.4p = 1540
p = 1540/4.4
p = 350
The profit p = Rs, 350
Hence, The cost price of the bag = 3.4p = 3.4 x 350 = Rs. 1190.
Let C.P =Rs. x
Then as given, (753 - x ) = (x - 455)
=>2x = 1208 => x = 604
There fore S.P= 150% of 604 => Rs. = Rs.906
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