3 pairs of gloves = 2 x 54 = 108 ; 1 pairs of gloves = 36
3 pairs of leg pads = 2 x 36 = 1 pairs of leg pads = 24
3 cricket balls = 2 x 24 = 48
cost of 1 cricket ball = 16;
Profit on 1st part Profit on 2nd part | ||
8% | Mean Profit 14% |
18% |
4 | 6 |
Ration of 1st and 2nd parts = 4 : 6 = 2 : 3
∴ Quantity of 2nd kind = | ❨ | 3 | x 1000 | ❩kg | = 600 kg. |
5 |
= | ❨ | 150 x | 5 | ❩m/sec |
18 |
= | ❨ | 125 | ❩m/sec. |
3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
Required time = | ❨ | 2000 x | 3 | ❩sec = 48 sec. |
125 |
Speed = | ❨ | 72 x | 5 | ❩m/sec | = 20 m/sec. |
18 |
Time = 26 sec.
Let the length of the train be x metres.
Then, | x + 250 | = 20 |
26 |
⟹ x + 250 = 520
⟹ x = 270.
Area to be plastered | = [2(l + b) x h] + (l x b) |
= {[2(25 + 12) x 6] + (25 x 12)} m2 | |
= (444 + 300) m2 | |
= 744 m2. |
∴ Cost of plastering = Rs. | ❨ | 744 x | 75 | ❩ | = Rs. 558. |
100 |
Balance = Rs. (7400 - 370) = Rs. 7030.
Ratio of their investments = (6500 x 6) : (8400 x 5) : (10000 x 3)
= 39000 : 42000 : 30000
= 13 : 14 : 10
∴ B's share = Rs. | ❨ | 7030 x | 14 | ❩ | = Rs. 2660. |
37 |
Then, | [ | P | ❨ | 1 + | 10 | ❩ | 2 | - P | ] | = 525 |
100 |
⟹ | P | [ | ❨ | 11 | ❩ | 2 | - 1 | ] | = 525 |
10 |
⟹ P = | ❨ | 525 x 100 | ❩ | = 2500. |
21 |
∴ Sum = Rs . 2500.
So, S.I. = Rs. | ❨ | 2500 x 5 x 4 | ❩ | = Rs. 500 |
100 |
699 |
301 |
1000 |
301 |
1000 |
301 |
log2 10 = | 1 | = | 1 | = | 10000 | = | 1000 | . |
log10 2 | 0.3010 | 3010 | 301 |
Then, x + y = | 1 | and 16x + 44y = 1. |
30 |
Solving these two equations, we get: x = | 1 | and y = | 1 |
60 | 60 |
∴ B's 1 day's work = | 1 | . |
60 |
Hence, B alone shall finish the whole work in 60 days.
Then, | ❨ | 85000 x 12 | = | 3 | ❩ |
42500 x x | 1 |
⟹ x = | ❨ | 85000 x 12 | ❩ | = 8. |
42500 x 3 |
So, B joined for 8 months.
4 | x y = (5 x 1 + 4) = 9 -------- 5 | y -1 x = (4 x y + 1) = (4 x 9 + 1) = 37 -------- | 1 -4 Now, 37 when divided successively by 5 and 4, we get 5 | 37 --------- 4 | 7 - 2 --------- | 1 - 3 Respective remainders are 2 and 3.
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