Tota profit percentage = (119 x 100/85) - 100 = 3400/85 = 40%
Let C.P. = Rs. C.
Then, 832 - C = C - 448
2C = 1280 => C = 640
Required S.P. = 150% of Rs. 640 = 150/100 x 640 = Rs. 960.
When the water is freely available and all the water is sold at the price of the milk, then the water gives the profit on the cost of 20 litres of milk.
Since, the profit % =
Therefore, profit percentage = = 25%
cost price = (225 + 15) = 240 sell price = 300
gain = (60/240)*100 = 25%
CP = 100, SP (with tax) =120
New SP = 100 - 5 = 95
Effective discount = 120 - 95 = 25
So, at SP of 95 ----> discount = 25
and at SP of 3325 -----> discount =
Given M.P=45,S.P=42, Profit = 0.05
Let C.P=x , Then
Profit = (42-x)/x = 0.05
=> x = 40.
Let the shopkeeper buy 300g for Rs.300. Now he sells 100g for Rs.110, another 100g for Rs120, and the rest 100g for Rs94.
Therefore, the total amount he receives = Rs.110 + Rs.120 + Rs.94 = 324.
Therefore, the shopkeeper spends Rs.300 and gets back Rs.324.
Therefore, his profit percentage = % = 8%
Cost price of 25 kg = Rs. (15 x 14.50 + 10 x 13) = Rs. 347.50.
Sell price of 25 kg = Rs. (25 x 15) = Rs. 375.
profit = Rs. (375 ? 347.50) = Rs. 27.50.
Let cp= 100,
35 % increase in sp=135
10 % discount in 135((135*10)/100)=13.5
so 1st sp=(135-13.5)=121.5, again 15 % discount in 1st sp((121.5*15)/100)=18.225
2nd sp=(121.5-18.225)=103.275,
so finally cp=100,sp=103.275 ,gain by 3.27%
Let the article costs 'X' to A
Cost price of B = 1.2X
Cost price of C = 0.75(1.2X) = 0.9X
Cost price of D = 1.4(0.9X) = 1.26X = 252
Amount paid by A for the article = Rs. 200.
If the price of the oranges decreases by 10%, the woman would save 10% of the money that is Rs.50 to buy the same amount as before.Now in Rs. 50 she can buy 2 kg more, therefore the current price of 1 kg of oranges is Rs25.Now, this current price is after 10% reduction.
Therefore, the original price = 25/0.9 = Rs. 27.77
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