A B C
investment 3x 4x 5x
Rate of return 6y% 5y% 4y%
Return
Total = (18+20+20) =
B's earnings - A's earnings = = 250
Total earning = = 7250
Initially CP profit SP MP
100 x (100+x) 133.33
After Change 100 2x (100+x)
Now, Since (100+x) - 100 = 2x
x= 20%
CP Profit SP MP
100 20 120 133.33
So, 300 60 360 400
Again 300 120 420
So the increased selling price = Rs. 420
Total cost of 4 cars = 1+2 = 3 lakh
Total S.P of 4 cars = 3 x 1.5 = 4.5 lakh ( )
S.P of 1 car = 1.2 lakh
S.P of rest 3 cars = 4.5 - 1.2 = 3.3 lakh
Average S.P of all the 3 cars = 1.1 lakh
Let the cost of Production = Rs. P
Then, as per question,
=1265
=> P=800
SP2 = 2/3 SP1
CP = 100
SP2 = 80
2/3 SP1 = 80
SP1 = 120
100 --- 20 => 20%
Let the new S.P be x, then
(100 - loss%) : (1st S.P.) = (100 + gain%) : (2nd S.P.)
=> x = 1260
SP of first article = Rs.1000
Profit = 20%
SP of Second Article = Rs.1000
Loss = 20%
So, Total SP = Rs.2000; Total CP = Rs.6250/3
As the CP is more than SP, he makes a loss.
Loss = CP - SP = (6250/3) - 2000 = Rs.(250/3)
So, Loss Percent = Lossx100/CP = 4%
33.33% profit means there is one part water and 3 part is pure wine. so the required ratio of water and wine in the mixture is 1:3
Cost Price of 5 kg = Rs.(14*2 + x*3) = (28 + 3x).
Sell price of 5 kg = Rs. (22x5) = Rs. 110.
[{110 - (28 + 3x)}/(28 + 3x) ]* 100 =10
[82-3x/28 + 3x]= 1 / 10
820 - 30x = 28 +3x
33x = 792
x = 24
110% of S.P. = Rs. 616
S.P. = (616 x 100)/110 = Rs. 560
C.P = (110 x 560)/112 = Rs. 500
when the water is freely available and all the water is sold at the price of the milk, then the water gives the profit on the cost of 20 liters of milk.
Therefore, profit percentage = (5/20) x 100 =25 % [ Profit %= (Profit/C.P)*100]
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