Let original Cost price is x
Its Selling price = (105/100) * x = 21x/20
New Cost price = (95/100) * x = 19x/20
New Selling price = (110/100 )* (19x/20 )= 209x/200
[(21x/20) - (209x/200)] = 1
=> x = 200
103.33 CP- 0.95 CP = 65
CP = Rs. 780
profit (%) = (936 - 780)/780 x 100 = 20%
Let the S.P = 100
then C.P. = 25
Profit = 75
Profit% = (75/25) * 100 = 300%
Cost Price of 2 dozen oranges Rs. (5 + 4) = Rs. 9.
Sell price of 2 dozen oranges = Rs. 11.
If profit is Rs 2, oranges bought = 2 dozen.
If profit is Rs. 50, oranges bought = (2/2) * 50 dozens = 50 dozens.
Recall it is based on inverse proportion or product constancy concept.
Reducion in price increase in amount
25% 1/4 1/3 33.33% = 4 oranges
It means original number of oranges = 4 x 3 = 12
original price of oranges = 16/12 = Rs. 1.33
Cost Price = = Rs. 7000. Let the labelled price be Rs. x.
Then,
= Rs.10000
Let the new S.P be x, then
(100 - loss%) : (1st S.P.) = (100 + gain%) : (2nd S.P.)
=> x = 1260
SP2 = 2/3 SP1
CP = 100
SP2 = 80
2/3 SP1 = 80
SP1 = 120
100 --- 20 => 20%
Let the cost of Production = Rs. P
Then, as per question,
=1265
=> P=800
Total cost of 4 cars = 1+2 = 3 lakh
Total S.P of 4 cars = 3 x 1.5 = 4.5 lakh ( )
S.P of 1 car = 1.2 lakh
S.P of rest 3 cars = 4.5 - 1.2 = 3.3 lakh
Average S.P of all the 3 cars = 1.1 lakh
Initially CP profit SP MP
100 x (100+x) 133.33
After Change 100 2x (100+x)
Now, Since (100+x) - 100 = 2x
x= 20%
CP Profit SP MP
100 20 120 133.33
So, 300 60 360 400
Again 300 120 420
So the increased selling price = Rs. 420
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