Let C.P. be Rs. x.
Then,= >
=> 1920 - x = x - 1280
=> 2x = 3200
=> x = 1600
Required S.P. = 125% of Rs. 1600 =Rs(125/100*1600) = Rs2000
Least Cost Price = Rs. (200 * 8) = Rs. 1600.
Greatest Selling Price = Rs. (425 * 8) = Rs. 3400.
Required profit = Rs. (3400 - 1600) = Rs. 1800.
Let the cost price of 1-liter pure milk be Re.1, then
8 litre mixture =>
SP => 8 x 2 = Rs. 16
Profit % =
Gain % = %
=
= 21%
Let the C.P be Rs.100 and S.P be Rs.x, Then
The profit is (x-100)
Now the S.P is doubled, then the new S.P is 2x
New profit is (2x-100)
Now as per the given condition;
=> 3(x-100) = 2x-100
By solving, we get
x = 200
Then the Profit percent = (200-100)/100 = 100
Hence the profit percentage is 100%
Let C.P. of each article be Re. 1 C.P. of x articles = Rs. x.
S.P. of x articles = Rs. 20.
Profit = Rs. (20 - x).
=> 2000 - 100x = 25x
=> 125x=2000
=> x=16
Friends, we know we will need gain amount to get gain percent, right. So lets get gain first.
Let the cost price of 1 pen is Re 1
Cost of 8 pens = Rs 8
Selling price of 8 pens = 12
Gain = 12 - 8 = 4
Gain% = % = % = 50%
Cost Price = = Rs. 7000. Let the labelled price be Rs. x.
Then,
= Rs.10000
Recall it is based on inverse proportion or product constancy concept.
Reducion in price increase in amount
25% 1/4 1/3 33.33% = 4 oranges
It means original number of oranges = 4 x 3 = 12
original price of oranges = 16/12 = Rs. 1.33
Cost Price of 2 dozen oranges Rs. (5 + 4) = Rs. 9.
Sell price of 2 dozen oranges = Rs. 11.
If profit is Rs 2, oranges bought = 2 dozen.
If profit is Rs. 50, oranges bought = (2/2) * 50 dozens = 50 dozens.
Let the S.P = 100
then C.P. = 25
Profit = 75
Profit% = (75/25) * 100 = 300%
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