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- Question
A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ?
Options- A. 10 sec
- B. 48 sec
- C. 36 sec
- D. 56 sec
- Correct Answer
- 36 sec
ExplanationGiven speed of jogger = 9 kmph
Speed of train = 45 kmph
As they are in same direction,
Relative speed = 45 - 9 = 36 kmph = 36x5/18 = 10 m/s
Distance = 240 + 120 = 360 mts
Time = distance/speed = 360/10 = 36 sec. - 1. How many seconds will a 600 m long train take to cross a man walking with a speed of 7 km/hr in the direction of the moving train if the speed of the train is 67 km/hr ?
Options- A. 29 sec
- B. 58 sec
- C. 36 sec
- D. 44 sec Discuss
- 2. 5 hrs after a goods train passed a station, another train travelling at a speed of 70 km/hr following that goods train passed through that station. If after passing the station the train overtakes the goods train in 9 hours. What is the speed of the goods train?
Options- A. 45 km/hr
- B. 54 km/hr
- C. 67.5 km/hr
- D. 36 km/hr Discuss
- 3. A train takes 10 sec to cross a bridge of length 100 m travelling at 90 kmph. Find the length of the train in meters.
Options- A. 130
- B. 120
- C. 140
- D. 150 Discuss
- 4. Two trains move from stations M and N. Both trains move towards each other at speeds of 54 km/hr and 63 km/hr respectively. When they meeteach other, the second train has travel 100 km more than the first. What is the distance (in km) between M and N
Options- A. 600
- B. 700
- C. 1300
- D. 1500 Discuss
- 5. A 260 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train ?
Options- A. 240 mts
- B. 270 mts
- C. 260 mts
- D. 250 mts Discuss
- 6. Train A can cross a man in 8 sec and a 180 m long platform ?P? in 17 sec. If train A cross train B which is running in opposite direction at speed of 108 km/hr in 8 sec, then find time taken by train B to cross platform P?
Options- A. 16 sec
- B. 11 sec
- C. 14 sec
- D. 12 sec Discuss
- 7. The ratio of the speed of Two trains is 5:8. Sum of their length is 660. The ratio of time taken to cross an Electric Pole by train A and B is 4:3. What is the difference between the length of two trains?
Options- A. 50m
- B. 40m
- C. 60m
- D. 45m Discuss
- 8. A train is moving at the speed of 72 km/hr. How many seconds will it take to cover a distance of 1400 m ?
Options- A. 70
- B. 80
- C. 72
- D. 84 Discuss
- 9. Train A takes 1 hour more than train B to travel a distance of 720 km. Due to engine trouble speed of train B falls by a third, so it takes 3 hours more than Train A to complete the same journey? What is the speed of Train A (in km/hr)?
Options- A. 80
- B. 90
- C. 60
- D. 70 Discuss
- 10. A uniformly moving train of length 480 m takes 3 minutes to completely cross a platform. If the same train, with the same speed crosses a pole completely in 30 sec, then the length of the platform is -
Options- A. 1 km
- B. 600 m
- C. 4.8 km
- D. 1.2 km Discuss
Problems on Trains
Search Results
Correct Answer: 36 sec
Explanation:
Speed of train relative to man = 67 - 7 = 60 km/hr.
= 60 x 5/18 = 50/3 m/sec.
Time taken to pass the man = 600 x 3/50 = 36 sec.
Correct Answer: 45 km/hr
Correct Answer: 150
Correct Answer: 1300
Correct Answer: 240 mts
Explanation:
Relative speed = 120 + 80 = 200 km/hr.
= 200 x 5/18 = 500/9 m/sec.
Let the length of the other train be L mts.
Then, (L + 260)/9 = 500/9 => L = 240 mts.
Correct Answer: 14 sec
Explanation:
Let length of train A be ?L? m and speed be ?V? m/s
ATQ ?
V =
Correct Answer: 60m
Explanation:
Ans.
Given that length of first train + length of second train = 660
Speed of first train : Speed of second train = 5:8 =5x : 8x
Time taken to cross the poll by two trains = 4:3 =4y:3y
Now ,
(5x*4y) + (8x*3y) = 660
44xy = 660
xy = 15
L1 - L2 = 24xy -20xy = 4xy = 60 m
Correct Answer: 70
Correct Answer: 80
Correct Answer:
Explanation:
Let length of platform be ?y?metres.
Then, at the platform,Distance travelled = y + (length of train) = (y + 480)m
Then, Speed of train = (y + 480)m / (3x60) sec = (y+480)/180 ...(1)
Also, at the pole,Distance travelled = length of train = 480m
Then, Speed of train = 480m / 30sec = 16 m/s ...(2)
Equating eq.(1) & eq.(2), we get,
(y+480)/180 = 16(y+480) = 16 x 180 = 2880
y = 2880 ?480 = 2400m or 2.4 km long platform.
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