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- Question
The time taken by a train 160 m long, running at 72 km/hr, in crossing an electric pole is
Options- A. 8 sec
- B. 9 sec
- C. 6 sec
- D. 4 sec
- Correct Answer
- 8 sec
- 1. Two trains are moving in the opposite direction at speed of 30 km/hr and 45 km/hr respectively, whose lengths are 450 m and 550 m respectively. What is the time taken (in seconds) by slower train to cross the faster train?
Options- A. 48
- B. 54
- C. 62
- D. 72 Discuss
- 2. A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less for the same journey. Find the speed of the train?
Options- A. 42 kmph
- B. 43 kmph
- C. 40 kmph
- D. 45 kmph Discuss
- 3. Train X crosses a stationary train Y in 60 seconds and a pole in 25 seconds with the same speed. The length of the train X is 300 m. What is the length of the stationary train Y ?
Options- A. 360 m
- B. 420 m
- C. 460 m
- D. 320 m Discuss
- 4. The length of a brigade which a train 130 m long and traveling at 45kmph can cross in 30 seconds, is
Options- A. 196 mts
- B. 220 mts
- C. 230 mts
- D. 245 mts Discuss
- 5. Two trains, one from Hyderabd to Bangalore and the other from Bangalore to Hyderabad, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is ?
Options- A. 3 : 4
- B. 4 : 3
- C. 2 : 3
- D. 3 : 2 Discuss
- 6. Excluding stoppages, the speed of a train is 120 kmph and including stoppages, it is 50 kmph. For how many minutes does the train stop per hour?
Options- A. 25
- B. 40
- C. 35
- D. 20 Discuss
- 7. A train moving at 2/3 rd of its normal speed reaches its destination 20 minutes late. Find the normal time taken ?
Options- A. 4/3 hrs
- B. 2/3 hrs
- C. 3/2 hrs
- D. 1/4 hrs Discuss
- 8. A jogger running at 9 km/hr along side a railway track is 260 m ahead of the engine of a 140 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger ?
Options- A. 25 sec
- B. 40 sec
- C. 38 sec
- D. 32 sec Discuss
- 9. Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is ?
Options- A. 42 sec
- B. 44 sec
- C. 46 sec
- D. 48 sec Discuss
- 10. A 260 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train ?
Options- A. 240 mts
- B. 270 mts
- C. 260 mts
- D. 250 mts Discuss
Problems on Trains
Search Results
Correct Answer: 48
Correct Answer: 40 kmph
Explanation:
We know that, Speed = Distance/time
Let the speed of the train be = x kmph
NORMAL SPEED SPEED 5 KMPH MORE
Distance = 360 Km Distance =360
speed = X Kmph Speed = (x+5)
Time =360/X Time =360/(x+15)
For the same journey if the speed increased 10 kmph more it will take 1 hour less
Time with original speed - time with increased speed = 1
=> (360/x) - (360/x+10) = 1
=> (360(x+5)-360x)/x(x+5) =1
=> 360X + 1800 -360X = X(X+5)
=> X^2 + 5x - 1800 = 0
X = 40 or -45
X cannot be negetive value
X = 40 kmph.
Correct Answer: 420 m
Explanation:
Let the length of the stationary train Y be LY
Given that length of train X, LX = 300 m
Let the speed of Train X be V.
Since the train X crosses train Y and a pole in 60 seconds and 25 seconds respectively.
=> 300/V = 25 ---> ( 1 )
(300 + LY) / V = 60 ---> ( 2 )
From (1) V = 300/25 = 12 m/sec.
From (2) (300 + LY)/12 = 60
=> 300 + LY = 60 (12) = 720
=> LY = 720 - 300 = 420 m
Length of the stationary train = 420 m
Correct Answer: 245 mts
Explanation:
Let the length of the brigade is x mts
Then Distance = 130 + x mts
given speed = 45 kmph = 45 x5/18 m/s
Time = 30 sec
T = D/S
=> 30 = 130+x/(45x5/18)
=> x = 245 mts.
Correct Answer: 4 : 3
Explanation:
Let us name the trains as A and B.
Then, (A's speed) : (B's speed)
= ?b : ?a = ?16 : ?9 = 4:3
Correct Answer: 35
Correct Answer: 2/3 hrs
Explanation:
Let the original speed and time is S and T
then distance = S x T
Now the speed changes to 2/3S and T is T+20
As the distance is same
S x T = 2/3Sx(T+20)
solving this we get t = 40 minutes
=40/60 = 2/3 hour
Correct Answer: 40 sec
Explanation:
Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 x 5/18 = 10 m/sec.
Distance to be covered = 260 + 140 = 400 m.
Time taken = 400/10 = 40 sec.
Correct Answer: 48 sec
Explanation:
Relative speed = 60 + 90 = 150 km/hr.
= 150 x 5/18 = 125/3 m/sec.
Distance covered = 1.10 + 0.9 = 2 km = 2000 m.
Required time = 2000 x 3/125 = 48 sec.
Correct Answer: 240 mts
Explanation:
Relative speed = 120 + 80 = 200 km/hr.
= 200 x 5/18 = 500/9 m/sec.
Let the length of the other train be L mts.
Then, (L + 260)/9 = 500/9 => L = 240 mts.
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