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- Question
The length of a brigade which a train 130 m long and traveling at 45kmph can cross in 30 seconds, is
Options- A. 196 mts
- B. 220 mts
- C. 230 mts
- D. 245 mts
- Correct Answer
- 245 mts
ExplanationLet the length of the brigade is x mts
Then Distance = 130 + x mts
given speed = 45 kmph = 45 x5/18 m/s
Time = 30 sec
T = D/S
=> 30 = 130+x/(45x5/18)
=> x = 245 mts. - 1. Two trains, one from Hyderabd to Bangalore and the other from Bangalore to Hyderabad, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is ?
Options- A. 3 : 4
- B. 4 : 3
- C. 2 : 3
- D. 3 : 2 Discuss
- 2. A train covered k km at 40 kmph and another 2k km at 20 kmph. Find the average speed of the train in covering the entire 3k km ?
Options- A. 28 kmph
- B. 24 kmph
- C. 26 kmph
- D. 32 kmph Discuss
- 3. A train 900 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is ?
Options- A. 400 m
- B. 300 m
- C. 500 m
- D. 600 m Discuss
- 4. How much time will a train of length 200 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction ?
Options- A. 58 sec
- B. 62 sec
- C. 60 sec
- D. 50 sec Discuss
- 5. A train for Fathehpur leaves for every 2 hrs 30 min from Agra station. An announcement was made that train left 37 mins ago and next train comes at 17:00hrs. At what time was the announcement made ?
Options- A. 15:07 hrs
- B. 15:20 hrs
- C. 15:05 hrs
- D. 15:00 hrs Discuss
- 6. Train X crosses a stationary train Y in 60 seconds and a pole in 25 seconds with the same speed. The length of the train X is 300 m. What is the length of the stationary train Y ?
Options- A. 360 m
- B. 420 m
- C. 460 m
- D. 320 m Discuss
- 7. A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less for the same journey. Find the speed of the train?
Options- A. 42 kmph
- B. 43 kmph
- C. 40 kmph
- D. 45 kmph Discuss
- 8. Two trains are moving in the opposite direction at speed of 30 km/hr and 45 km/hr respectively, whose lengths are 450 m and 550 m respectively. What is the time taken (in seconds) by slower train to cross the faster train?
Options- A. 48
- B. 54
- C. 62
- D. 72 Discuss
- 9. The time taken by a train 160 m long, running at 72 km/hr, in crossing an electric pole is
Options- A. 8 sec
- B. 9 sec
- C. 6 sec
- D. 4 sec Discuss
- 10. Excluding stoppages, the speed of a train is 120 kmph and including stoppages, it is 50 kmph. For how many minutes does the train stop per hour?
Options- A. 25
- B. 40
- C. 35
- D. 20 Discuss
Problems on Trains
Search Results
Correct Answer: 4 : 3
Explanation:
Let us name the trains as A and B.
Then, (A's speed) : (B's speed)
= ?b : ?a = ?16 : ?9 = 4:3
Correct Answer: 24 kmph
Explanation:
Total time taken = k/40 + 2k/20 hours
= 5k/40 = k/8 hours
Average speed = 3k/(k/8) = 24 kmph.
Correct Answer: 400 m
Explanation:
Speed = 78 x 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (900 + x)/60 = 65/3
x = 400 m.
Correct Answer: 50 sec
Explanation:
The distance to be covered = Sum of their lengths = 200 + 300 = 500 m.
Relative speed = 72 -36 = 36 kmph = 36 x 5/18 = 10 mps.
Time required = d/s = 500/10 = 50 sec.
Correct Answer: 15:07 hrs
Explanation:
Next train comes at 17:00 hrs.
So, last train will be = 17:00hrs - 2:30hrs
= 14:30hrs
Announcement made after 37 min of the last train.
S0, 14:30hrs + 00:37 min
= 15:07 hrs.
Correct Answer: 420 m
Explanation:
Let the length of the stationary train Y be LY
Given that length of train X, LX = 300 m
Let the speed of Train X be V.
Since the train X crosses train Y and a pole in 60 seconds and 25 seconds respectively.
=> 300/V = 25 ---> ( 1 )
(300 + LY) / V = 60 ---> ( 2 )
From (1) V = 300/25 = 12 m/sec.
From (2) (300 + LY)/12 = 60
=> 300 + LY = 60 (12) = 720
=> LY = 720 - 300 = 420 m
Length of the stationary train = 420 m
Correct Answer: 40 kmph
Explanation:
We know that, Speed = Distance/time
Let the speed of the train be = x kmph
NORMAL SPEED SPEED 5 KMPH MORE
Distance = 360 Km Distance =360
speed = X Kmph Speed = (x+5)
Time =360/X Time =360/(x+15)
For the same journey if the speed increased 10 kmph more it will take 1 hour less
Time with original speed - time with increased speed = 1
=> (360/x) - (360/x+10) = 1
=> (360(x+5)-360x)/x(x+5) =1
=> 360X + 1800 -360X = X(X+5)
=> X^2 + 5x - 1800 = 0
X = 40 or -45
X cannot be negetive value
X = 40 kmph.
Correct Answer: 48
Correct Answer: 8 sec
Correct Answer: 35
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