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- Question
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is ?
Options- A. 45 kmph
- B. 25 kmph
- C. 30 kmph
- D. 50 kmph
- Correct Answer
- 50 kmph
ExplanationSpeed of the train relative to man = (125/10) m/sec = (25/2) m/sec.
[(25/2) x (18/5)] km/hr = 45 km/hr.
Let the speed of the train be 'S' km/hr.
Then, relative speed = (S - 5) km/hr.
S - 5 = 45 => S = 50 km/hr. - 1. Two trains namely X & Y leave station 'A' at 6.30am and 7.40am and travel at 30km/hr and 40 km/hr respectively. How many kms from 'A' will the trains meet ?
Options- A. 140 kms
- B. 120 kms
- C. 96 kms
- D. 142 kms Discuss
- 2. Two goods trains each 520 m long, are running in opposite directions on parallel tracks. Their speeds are 42 km/hr and 36 km/hr respectively. Find the time taken by the slower train to cross the driver of the faster one ?
Options- A. 60 sec
- B. 48 sec
- C. 45 sec
- D. 34 sec Discuss
- 3. Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?
Options- A. 27 7/9 mts
- B. 25 8/7 mts
- C. 21 1/4 mts
- D. 22 mts Discuss
- 4. Find the length of a train if it takes 10 seconds to cross a pole and double of this time to cross a platform of length 200 mts ?
Options- A. 180 mts
- B. 190 mts
- C. 200 mts
- D. 210 mts Discuss
- 5. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is ?
Options- A. 1 : 2
- B. 3 : 1
- C. 4 : 7
- D. 3 : 2 Discuss
- 6. A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Options- A. 5
- B. 6
- C. 7
- D. 10 Discuss
- 7. The length of two superfast trains are 140 mts and 160 mts respectively. If they run at the speed of 60 km/hr and 80 km/hr respectively in opposite direction, find the time in which they will cross each other ?
Options- A. 7.71 sec
- B. 10.48 sec
- C. 9.36 sec
- D. 8.45 sec Discuss
- 8. Agra and Delhi are 160 km apart. A train leaves Agra for Delhi and at the same time another train leaves Delhi for Agra. Both the trains meet 5 hrs after they start moving. If the train travelling from Agra to Delhi travels 6 km/hr faster than the other train, find the speed of the faster train?
Options- A. 19 kmph
- B. 13 kmph
- C. 7 kmph
- D. 9 kmph Discuss
- 9. An Engine length 1000 m moving at 10 m/s. A bird is flying from engine to end with 'x' m/s and coming back at '2x' m/s. Take total time of bird travelling as 187.5 s. Find x and 2x in km/hr ?
Options- A. 21.4 and 42.8
- B. 25.2 and 50.4
- C. 31.4208 and 62.8416
- D. 33.12 and 66.24 Discuss
- 10. Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 16 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is ?
Options- A. 387 kms
- B. 242 kms
- C. 145 kms
- D. 444 kms Discuss
Problems on Trains
Search Results
Correct Answer: 140 kms
Explanation:
It is given train X leave station A at 6:30 am, here it is asked to calculate the distance from A when the trains meet, the
Distance traveled by train left at 6:30 am upto 7:40 am i.e. in 1 hr. 10 min. or 7/6 hours = 30 x 7/6 = 35 km
So train leaving at 7:40 am will meet first train after covering a distance of 35 km. with relative speed of 40-30=10 km/hr.
Hence time taken = 35/10 = 3.5 hours or 3 hours 30 minutes
So distance from A = Distance traveled by 2nd train in 3 hr. 30 min
= 40 x 3.5 = 140 km.
Correct Answer: 48 sec
Explanation:
Relative speed = 42 + 36 = 78 km/hr = m/s
Distance = (520 + 520) =1040 mts.
Time = = 48 sec
Correct Answer: 27 7/9 mts
Correct Answer: 200 mts
Explanation:
Let the length of the train be 'L' mts
let the speed of the train be 'S' m/s
Given it crosses a pole in 10 sec=> L/S = 10 ......(1)
Given it takes 20 sec (double of pole) to cross a platform of length 200 mts
=> (L + 200)/S = 20
=> L/S + 200/S = 20
But from (1) L/S = 10
=> 200/S = 20 - 10
=> S = 20 m/s
Then, from (1)
=> L = 10 x 20 = 200 mts.
Hence, the length of the train = 200 mts.
Correct Answer: 3 : 2
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27 x meters, and
length of the second train = 17 y meters.
(27 x + 17 y) / (x + y) = 23
=> 27 x + 17 y = 23 x + 23 y
=> 4 x = 6 y
=> x/y = 3/2.
Correct Answer: 6
Explanation:
Speed of train relative to man = (60 + 6) km/hr = 66 km/hr.
[66*(5/18)] m/sec = (55/3) m/sec
Time taken to pass the man = [110*(3/55)]m/sec = 6 sec.
Correct Answer: 7.71 sec
Explanation:
Given L1 = 140 m
L2 = 160 m
S1 = 60 km/hr
S2 = 80 km/hr
From the question we get,
S1 + S2 = (L1 + L2) / T
=> (60 + 80) 5/18 m/s = 140 + 160/T
=> T = 54/7 = 7.71 sec
Correct Answer: 19 kmph
Explanation:
Let the speed of the slower train = p kmph
ATQ,
Speed of the faster train = (p + 6) kmph
Then,
(p + p + 6) x 5 = 160
10p + 30 = 160
10p = 130
p = 13 kmph
Then, speed of the faster train = p + 6 = 13 + 6 = 19 kmph.
Correct Answer: 31.4208 and 62.8416
Explanation:
Birds speeds in mtrs/sec is 'x' and '2x' .
While flying from Engine to end, relative speed = (x+10) m/sec
from end to engine, flying speed = (2x - 10) mtr/sec
so
1000/(x+10) + 1000/(2x-10) = 187.5 secs
solving it, we get
so x = 8.728 m/sec and 2x= 17.456 m/sec
x = 31.4208 km/hr and 2x = 62.8416 km/hr.
Correct Answer: 444 kms
Explanation:
1h ----- 5 kms
? ------ 60 kms
Time = 12 hrs
Relative Speed = 16 + 21 = 37 kmph
T = 12 hrs
D = S x T = 37 x 12 = 444 kms.
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