Let the length of the train be 'L' mts
let the speed of the train be 'S' m/s
Given it crosses a pole in 10 sec=> L/S = 10 ......(1)
Given it takes 20 sec (double of pole) to cross a platform of length 200 mts
=> (L + 200)/S = 20
=> L/S + 200/S = 20
But from (1) L/S = 10
=> 200/S = 20 - 10
=> S = 20 m/s
Then, from (1)
=> L = 10 x 20 = 200 mts.
Hence, the length of the train = 200 mts.
4th observation i.e., 8 is the median.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
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