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- Question
Two trains are running at 60 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 6 seconds. What is the length of the fast train ? A. 6623 mts B. 6632 mts C.6345 mts D. 6354 mts
Options- A. Option A
- B. Option B
- C. Option C
- D. Option D
- Correct Answer
- Option A
ExplanationAs Trains are moving in same direction,
Relative Speed = 60-20 = 40 kmph
--> m/sec
Length of Train= Speed * Time
Length =
- 1. A train running at the speed of 40 km/hr crosses a signal pole in 9 seconds. Find the length of the train ?
Options- A. 90 mts
- B. 150 mts
- C. 120 mts
- D. 100 mts Discuss
- 2. A train sets off at 3 p.m. at the speed of 70 kmph. Another train starts at 4:30 p.m. in the same direction at the rate of 85 kmph. At what time the trains will meet ?
Options- A. 10:10 pm
- B. 9:50 pm
- C. 11:30 pm
- D. 10:30 pm Discuss
- 3. Length of train is 170 meters and speed of train is 63 km/hour. This train can pass a bridge in 30 seconds, then find the length of the bridge.
Options- A. 355 mts
- B. 325 mts
- C. 365 mts
- D. 312 mts Discuss
- 4. A jogger is running at 9 kmph alongside a railway track is 240 meters ahead of the engine of a 120 meters long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ?
Options- A. 48 sec
- B. 36 sec
- C. 18 sec
- D. 72 sec Discuss
- 5. A train is traveling at 48 kmph . It crosses another train having half of its length , traveling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. What is the length of the platform ?
Options- A. 500
- B. 400
- C. 360
- D. 480 Discuss
- 6. Train K crosses a stationary Train L in 50 seconds and a pole in 20 seconds with the same speed. The length of the Train K is 240 meters. What is the length of stationary Train L ?
Options- A. 60 mts
- B. 120 mts
- C. 240 mts
- D. 360 mts Discuss
- 7. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is ?
Options- A. 1 : 2
- B. 3 : 1
- C. 4 : 7
- D. 3 : 2 Discuss
- 8. Find the length of a train if it takes 10 seconds to cross a pole and double of this time to cross a platform of length 200 mts ?
Options- A. 180 mts
- B. 190 mts
- C. 200 mts
- D. 210 mts Discuss
- 9. Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?
Options- A. 27 7/9 mts
- B. 25 8/7 mts
- C. 21 1/4 mts
- D. 22 mts Discuss
- 10. Two goods trains each 520 m long, are running in opposite directions on parallel tracks. Their speeds are 42 km/hr and 36 km/hr respectively. Find the time taken by the slower train to cross the driver of the faster one ?
Options- A. 60 sec
- B. 48 sec
- C. 45 sec
- D. 34 sec Discuss
Problems on Trains
Search Results
Correct Answer: 100 mts
Explanation:
We know that
distance= speed * time
d= 100 mts.
Correct Answer: 11:30 pm
Explanation:
Distance = 70 x 1 ½ = 105 km
Relative Speed = 85 ? 70 = 15
Time = 105/15 = 7 hrs
4:30 + 7 hrs = 11.30 p.m.
Correct Answer: 355 mts
Explanation:
Given speed = 63 km/hr = m/s
Let the length of the bridge = x mts
Given time taken to cover the distance of (170 + x)mts is 30 sec.
We know speed = m/s
--> x = 355 mts.
Correct Answer: 36 sec
Correct Answer: 400
Correct Answer: 360 mts
Explanation:
Speed of the Train K is given by s = d/t = 240/20 = 12 m/s
Distance covered by Train K in 50 seconds = 12 x 50 = 600 mts.
But it crosses Train L in 50 seconds
Therefore, the length of the Train L is = 600 - 240 = 360 mts.
Correct Answer: 3 : 2
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27 x meters, and
length of the second train = 17 y meters.
(27 x + 17 y) / (x + y) = 23
=> 27 x + 17 y = 23 x + 23 y
=> 4 x = 6 y
=> x/y = 3/2.
Correct Answer: 200 mts
Explanation:
Let the length of the train be 'L' mts
let the speed of the train be 'S' m/s
Given it crosses a pole in 10 sec=> L/S = 10 ......(1)
Given it takes 20 sec (double of pole) to cross a platform of length 200 mts
=> (L + 200)/S = 20
=> L/S + 200/S = 20
But from (1) L/S = 10
=> 200/S = 20 - 10
=> S = 20 m/s
Then, from (1)
=> L = 10 x 20 = 200 mts.
Hence, the length of the train = 200 mts.
Correct Answer: 27 7/9 mts
Correct Answer: 48 sec
Explanation:
Relative speed = 42 + 36 = 78 km/hr = m/s
Distance = (520 + 520) =1040 mts.
Time = = 48 sec
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