Total distance covered = miles = miles
Time taken = hrs = hrs = = 3 min
Let the length of the train be L metres
Speed of first train = m/hour
Speed of secxond train = m/hour
When running in opposite directions, relative speed = 200 L + 300 L m/hour
Distance to be covered = L + L = 2L metre
Time taken = sec
=14.4 sec
Assume both trains meet after x hours after 7 am
Distance covered by train starting from P in x hours = 20x km
Distance covered by train starting from Q in (x-1) hours = 25(x-1)
Total distance = 110
=> 20x + 25(x-1) = 110
=> 45x = 135
=> x= 3
Means, they meet after 3 hours after 7 am, ie, they meet at 10 am
108 kmph = 108*[5/18] m/sec = 30 m / s.
Let the length of the train = L mts
Relative speed of train and man = 74 - 8 = 66 kmph = 66 x 5/18 m/s
=> 66 x 5/18 = L/9
=> L = 165 mts.
Speed of train 1 = = 12 m/sec
Speed of train 2 = = 8 m/sec
if they travel in opposite direction, relative speed = 12 + 8 = 20 m/sec
distance covered = 120 + 120 = 240 m
time = distance/speed = 240/20 = 12 sec
Relative speed = (120 + 80) km/hr
=(200*5/18)m/s = (500/9)m/s
Let the length of the other train be x metres.
Then, x+270/9 = 500/9
=> x + 270 = 500
=> x = 230.
Let the distance be 'd' kms.
According to the given data,
Given speed of the first train = 60 km/hr = 60 x 5/18 = 50/3 m/s
Let the speed of the second train = x m/s
Then, the difference in the speed is given by
=> x = 10 m/s
=> 10 x 18/5 = 36 km/hr
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