logo

CuriousTab

CuriousTab

Discussion


Home Aptitude Problems on Numbers Comments

  • Question
  • The sum of a non-zero number and 9 times its reciprocal is 10. What is the number?


  • Options
  • A. 10
  • B. 11
  • C. 9
  • D. 90

  • Correct Answer


  • Tags: Bank Exams

    Problems on Numbers


    Search Results


    • 1. What least number must be subtracted from 210, so that the sum is completely divisible by 11?

    • Options
    • A. 2
    • B. 3
    • C. 4
    • D. 1
    • Discuss
    • 2. What is the sum of the first 12 terms of an arithmetic progression if the first term is 3 and last term is 47?

    • Options
    • A. 260
    • B. 300
    • C. 280
    • D. 220
    • Discuss
    • 3. A non-zero number is greater than 7 times its reciprocal by 9.3. What is the number?

    • Options
    • A. 10
    • B. 20
    • C. 5
    • D. 14
    • Discuss
    • 4. What is the largest 4 digit number which is exactly divisible by 81?

    • Options
    • A. 9993
    • B. 9936
    • C. 9918
    • D. 9963
    • Discuss
    • 5. The least number that must be substracted from 63520 to make the result a perfect square is

    • Options
    • A. 30
    • B. 24
    • C. 14
    • D. 16
    • Discuss
    • 6. The average of four consecutive odd numbers is 40. What is the largest number?

    • Options
    • A. 42
    • B. 45
    • C. 43
    • D. 44
    • Discuss
    • 7. What is the remainder when 2468 is divided by 37?

    • Options
    • A. 26
    • B. 36
    • C. 18
    • D. 14
    • Discuss
    • 8. Of the 3 numbers whose average is 40, the first is 1/3 rd the sum of other 2. What is the first number?

    • Options
    • A. 20
    • B. 50
    • C. 25
    • D. 30
    • Discuss
    • 9. Convert binary 1101111 to decimal.

    • Options
    • A. 111
    • B. 101
    • C. 110
    • D. 100
    • Discuss
    • 10. The sum of a fraction and 7 times its reciprocal is 11/2. What is the fraction?

    • Options
    • A. 7/2
    • B. 2/7
    • C. 3/4
    • D. 4/3
    • Discuss


    Comments

    There are no comments.

Enter a new Comment