Number = 271 x 96 + 0 = 26016
=> 95) 26016 (273
25935
--------
81
Required number = 81.
Let x and y be the two parts of 96.
x/7 = y/9 => x:y = 7:9
=> The smallest part is = 7/16 x 96 = 42.
16200 =
A perfect cube has a property of having the indices of all its prime factors divisible by 3.
Required number = = 9x5 = 45.
Let the number be 'x'. Then, from given data
x/2 + x/3 + x/4 = x+22
13x/12 = x+22
x = 264
As per divisibility rule a number is divisible by 6 means it should be divisible by 2 and 3
case 1 : the divisibility rule for 2 is the number should be end with even number
in this case R =2 & R=4
case 2 : The divisibility rule for 3 is the sum of numbers should be divisible by 3
so if we take option (2) Q=1 & R=4 the sum is 39
if we take option (3) Q=1 & R=2 the sum is 37
So Option (2) is correct 39 is divided by 3
Let the ten's digit be x and unit's digit be y.
Then, (10x + y) - (10y + x) = 63
=> 9 (x - y) = 63
=> x - y = 7.
Thus, none of the numbers can be deermined..
Let the number be 3p and 5p
ATQ,
8p = 2 x 48
p = 96/8
p = 12
The numbers are 36 and 60.
Hence, the product of the numbers = 36 x 60 = 2160.
Let the larger number be p
Then, smaller number = 1/6 x p = p/6
Given difference between two numbers = 25
p - p/6 = 25
5p/6 = 25
5p = 150
p = 30
Then, p/6 = 30/6 = 5
Hence, larger number = 30 and smaller number = 5 which makes the difference = 25.
Let each literature text book cost be Rs. X
Then, cost of mathematics text book = Rs. (X + 2)
ATQ,
5X = 38 + 3(X + 2)
5X = 38 + 3X + 6
2X = 44
X = 22.
Therefore, cost of each literature text book = Rs. X = Rs. 22.
And that of masthematics = X + 2 = Rs. 24.
To find the largest 4 digit number exactly divisible by 88,
We should divide the largest possible 4 digit number by 88, and if we get any remainder than subtract it from that largest number.
The largest possible 4 digit number is 9999
Now,
88) 9999 (113
88
_______
119
88
_______
319
264
_______
55
_______
Therefore, the largest 4 digit number exactly divisible by 88 is given by
9999 - 55 = 9944.
Let the middle digit be x.
Then, 2x = 10 or x = 5. So, the number is either 253 or 352
Since the number increases on reversing the digits, so the hundred's digit is smaller than the unit's digit.
Hence, required number = 253.
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