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- Question
Half the people on a bus get off at each stop after the first, and no one gets on after the first stop. If only one person gets off at stop number 7, how many people got on at the first stop?
Options- A. 128
- B. 64
- C. 32
- D. 16
- Correct Answer
- 64
Explanation7th stop only one was left and in each preceding stop twice the nos... there were so 6 stops before 7th.
so
- 1. 40 % of 250 = 50% ?
Options- A. 200
- B. 100
- C. 150
- D. 400 Discuss
- 2. If the sum and diference of two numbers are 20 and 8 respectively, then the difference of their squares is :
Options- A. 120
- B. 140
- C. 160
- D. 180 Discuss
- 3. The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and 15 as remainder. What is the smaller number ?
Options- A. 270
- B. 1270
- C. 350
- D. 720 Discuss
- 4. The least number of four digits which is divisible by 4, 6, 8 and 10 is ?
Options- A. 1107
- B. 1080
- C. 1100
- D. 1208 Discuss
- 5. There are 15 lines in plane. How many intersections (Maximum) can be made ?
Options- A. 55
- B. 105
- C. 215
- D. 148 Discuss
- 6. There are 5 consecutive odd numbers. If the difference between square of the average of first two odd number and the of the average last two odd numbers is 396, what is the smallest odd number?
Options- A. 29
- B. 27
- C. 31
- D. 33 Discuss
- 7. Srinivas bought 10 cycles for Rs. 1,750 each. He sold 4 cycles for Rs 8,400, 3 for Rs 1900 each . At what price should he sell the remaining cycles so as to earn an average profit of Rs 320 per cycle ?
Options- A. Rs. 1580
- B. Rs. 2200
- C. Rs. 1785
- D. Rs. 1950 Discuss
- 8. Total 100 members are writing exam. In that 48 members are writing first exam, 45 members are writing second exam and 38 members are writing third exam. 5 members are writing all the three exams. How many members are writing 2 exams ?
Options- A. 26
- B. 23
- C. 27
- D. 21 Discuss
- 9. The series of differences between consecutive prime numbers is represented as Cp1, Cp2, Cp3, .... Cpn , Whare Cp1 is the difference between the second and the first prime number. Find the sum of series when n = 23, given that the 23rd prime number is 83 ?
Options- A. 87
- B. 81
- C. 83
- D. 85 Discuss
- 10. Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is :
Options- A. 83
- B. 89
- C. 85
- D. 79 Discuss
Problems on Numbers
Search Results
Correct Answer: 200
Explanation:
As per given
Correct Answer: 160
Explanation:
Let the numbers be x and y. Then, x + y = 20 and x - y = 8.
x^2 - y^2 = (x + y) (x - y) = 20 x 8 = 160.
Correct Answer: 270
Explanation:
Let the smallest number be x.
Then larger number = (x + 1365)
x + 1365 = 6x + 15
= 5x = 1350
x = 270
Smaller number = 270.
Correct Answer: 1080
Explanation:
LCM of 4, 6, 8 and 10 = 120
120) 1000 (8
960
------
40
The least number of four digits which is divisible by 4, 6, 8 and 10 => 1000 + 120 - 40 = 1080.
Correct Answer: 105
Explanation:
First line will cut all other 14, similarly second will cut 13, and so on
Total = 14+13+12+11+10+9+8+7+6+5+4+3+2+1 = 105.
Correct Answer: 29
Explanation:
Let the five consecutive odd numbers be x-4, x-2, x, x+2, x+4
According to the question,
Difference between square of the average of first two odd number and the of the average last
two odd numbers is 396
i.e, x+3 and x-3
Hence, the smallest odd number is 33 - 4 = 29.
Correct Answer: Rs. 2200
Explanation:
He sold 4 cycles for Rs. 8400
[It means each cycle price is Rs. 2100]
And again he sold 3 cycles for Rs. 1900 each
If he want to gain avg profit on each cycle is Rs. 320 per cycle.
So profit for 10 cycles is @ Rs.320 is,
10 x 320 = Rs. 3200
He already got Rs. 1850 profit by selling 7 cycles.
Now, remaining amount is 3200 - 1850 = 1350
So from remaining 3 cycles we want to get Rs. 1350 profit ,
1350/3 = 450
so he must sell remaining 3 cycles at Rs. 2200 each one.
Correct Answer: 21
Explanation:
Total number of exams written by 100 students = 48 + 45 + 38 = 131
Now let us say x members are writing only 1 exam, y members are writing only 2 exams, z members are writing only 3 exams.
Therefore, x + 2y + 3z = 131 also x + y + z = 100.
Given that z = 5. So x + 2y = 116 and x + y = 95.
Solving we get y = 21.
So 21 members are writing exactly 2 exams.
Correct Answer: 87
Explanation:
Cp1 = p2 - p1 ,
Cp2 = p3 - p2
..
..
..
Cp23 = p24 - p23
Sum of series = (p2-p1) + (p3-p2) + .....(p23-p22) + (p24-p23)
All terms get cancelled, except p1 = 2 and p24 = 89
So Sum = -p1 + p24
Sum of series = -2 + 89 = 87
Correct Answer: 85
Explanation:
Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F of 551 and 1073 = 29;
First number = 551/29 = 19
Third number = 1073/29 = 37.
Required sum = 19 + 29 + 37 = 85.
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