Multiplying two negatives (or any even multiple) results in a positive. But multiplying three negatives (or any odd multiple) gives a negative. If the result of multiplying 6 negatives is odd, the largest number of negative integers will be the largest odd number (i.e.5)
Let the smaller number be 'm'
Then, from the given data, the larger number is '3m'
Given that m + 3m = 44
=> 4m = 44
m = 44/4 = 11
=> m = 11
=> 3m = 3 x 11 = 33
Hence, the two numbers are 11 and 33.
(300 ? 101)/11 = 199/11 = 18 1/11
18 Numbers.
By hit and trail, we find that
47619 x 7 = 333333.
7) 333333 (47619
333333
----------------
0
And 476190476 x 7 = 3333333333 but smallest number is 47619.
Let the greater and smaller number be p and q respectively.
4q = p + 5 ------ (I)
p = 3q+2 ------- (II)
From equation (I) and (II)
q = 7
p = 23
Let the two no's be a and b;
Given product of the no's is p = ab;
If the each nos is increased by 2 then the new product will be
(a+2)(b+2) = ab + 2a + 2b + 4
= ab + 2(a+b) + 4
= p + 2(a+b) + 4
Hence the new product is (p+4) times greater than twice the sum of the two original numbers.
If a number to be divisile by 88, it should be divisible by both "8" and "11"
Check for '8' :
For a number to be divisible by "8", the last 3-digit should be divisible by "8"
Here 72x23y --> last 3-digit is '23y'
So y=2 [ (i.e) 232 is absolutely divisible by "8"]
Chech for '11' :
For a number to be divisible by "11" , sum of odd digits - sum of even digits should be divisible by "11"
(7 + x + 3) - (2 + 2 + y)
(7 + x + 3) - (2 + 2 + 2)
(10 + x) - 6 should be divisible by "11"
for x = 7
=> 17 - 6 = 11 [ which is absolutely divisible by "11"]
So x = 7 , y= 2.
Lowest 4-digit number is 1000.
LCM of 3, 4 and 5 is 60.
Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 - 40) = 1020.
Now, add the remainder 2 that's required. Thus, the answer is 1022.
Let the two-digit number be 10a + b
a + b = 12 --- (1)
If a>b, a - b = 6
If b>a, b - a = 6
If a - b = 6, adding it to equation (1), we get
2a = 18 => a =9
so b = 12 - a = 3
Number would be 93.
if b - a = 6, adding it to the equation (1), we get
2b = 18 => b = 9
a = 12 - b = 3.
Number would be 39.
There fore, Number would be 39 or 93.
Given
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 + 1 + 1
Using BODMAS Rule,
As multiplication precedes addition, 1 x 0 = 0,
Now, 10 + 0 + 1 + 1 = 10 + 2 = 12.
Hence, 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 + 1 + 1 = 12.
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