Let the number of girls = x
=> x + x + 4 = 12
=> 2x = 8
=> x = 4
=> Number of girls = 4
=> Number of boys = 4 + 4 = 8
Let the numbers be x and y. Then, 2x + 3y = 39...(i)and 3x + 2y = 30 ...(ii)
On solving (i) and (ii), we get : x = 6 and y = 9.
larger number = 9
Let the numerator be x Then, denominator = x + 3.
Now. (x + 4)/(x + 3) +4 = 4/5 <=> 5 (x + 4) = 4(x + 7)
=> x = 8.
The fraction is 8/11.
Let the ten's digit be x.
Then, unit's digit = x + 2.
Number = 10x + (x + 2) = 11x + 2
Sum of digits = x + (x + 2) = 2x + 2.
(11x + 2) (2x + 2) = 144
=> 22x^2+26x-140=0
=> (x - 2)(11x + 35) = 0
=> x = 2
Hence, Required Number = 11x + 2 = 24
Let the numbers be x and y.
Then, xy = 9375 and x/y = 15.
=>
=> y = 25
=> x = 15y = 15 x 25 = 375.
Sum of the numbers = 375 + 25 = 400.
Let the numbers be x, x + 2 and X + 4.
Then, x(x + 2)(x +4) / 8 = 720 => x(x + 2)(x +4) = 5760.
?x * ?(x + 2) * ?(x +4) = ?x(x +2)(x + 4 ) = ?5760 = 24?10.
(385/1001) = 5/13
First Number is 5
=> Fourth number is 13
Let the two parts be (54 - x) and x.
Then, 10 (54 - x) + 22x = 780
=> 12x = 240
=> x = 20.
Bigger part = (54 - x) = 34.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.