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- Question
The difference between the two numbers is 1365. When the larger number is divided by the smaller one, the quotient is 6 and the remainder is 15. The smaller number is?
Options- A. 280
- B. 270
- C. 370
- D. 170
- Correct Answer
- 270
ExplanationLet the numbers be x and 1365+x
Then 1365+x = 6x+15
=> x = 270
- 1. Three numbers are in the ratio 4 : 5 : 6 and their average is 25. The largest number is :
Options- A. 30
- B. 40
- C. 50
- D. 60 Discuss
- 2. Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is :
Options- A. 12
- B. 137
- C. 14
- D. 15 Discuss
- 3. In a two-digit number, the digit in the unit's place is more than twice the digit in ten's place by 1. If the digits in the unit's place and the ten's place are interchanged,difference between the newly formed number and the oiginal number is less than the original number by 1. What is the original number ?
Options- A. 35
- B. 36
- C. 37
- D. 39 Discuss
- 4. What is the place value of 6 in 64?
Options- A. 6
- B. 60
- C. 64
- D. 10 Discuss
- 5. The sum of present age of father and his son is 60 yrs. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be?
Options- A. 45
- B. 25
- C. 20
- D. 33 Discuss
- 6. The product of two numbers is 9375 and the quotient, when the larger one is divided by the smaller, is 15. The sum of the numbers is :
Options- A. 100
- B. 200
- C. 300
- D. 400 Discuss
- 7. In a two-digit number, if it is known that its unit's digit exceeds its ten's digit by 2 and that the product of the given number and the sum of its digits is equal to 144, then the number is :
Options- A. 12
- B. 24
- C. 36
- D. 48 Discuss
- 8. The denominator of a fraction is 3 more than the numerator. If the numerator as well as the denominator is increased by 4, the fraction becomes 4/5. What was the original fraction ?
Options- A. 7/11
- B. 8/11
- C. 9/11
- D. 10/11 Discuss
- 9. What approximate value will come in place of the question mark(?) in the below question? (47% of 1442 - 36% of 1412) + 63 = ?
Options- A. 4
- B. 5
- C. 3
- D. 6 Discuss
- 10. There are two numbers such that the sum of twice the first and thrice the second is 39, while the sum of thrice the first, and twice the second is 36. The larger of the two is :
Options- A. 3
- B. 6
- C. 9
- D. 12 Discuss
Problems on Numbers
Search Results
Correct Answer: 30
Explanation:
Let the numbers be 4x, 5x and 6x, Then, (4x + 5x + 6x ) / 3 = 25
=> 5x = 25
=> x = 5.
Largest number 6x = 30.
Correct Answer: 15
Explanation:
Let the three integers be x, x + 2 and x + 4. Then, 3x = 2 (x + 4) + 3 <=> x = 11.
Third integer = x + 4 = 15.
Correct Answer: 37
Explanation:
Let the ten's digit be x. Then, unit's digit = 2x + 1.
[10x + (2x + 1)] - [{10 (2x + 1) + x} - {10x + (2x + 1)}] = 1
<=> (12x + 1) - (9x + 9) = 1 <=> 3x = 9, x = 3.
So, ten's digit = 3 and unit's digit = 7. Hence, original number = 37.
Correct Answer: 60
Explanation:
We know that,
? Each digit has a fixed position called its place.
? Each digit has a value depending on its place called the place value of the digit.
? The face value of a digit for any place in the given number is the value of the digit itself
? Place value of a digit = (face value of the digit) × (value of the place).
Hence, the place value of 6 in 64 = 6 x 10 = 60.
Correct Answer: 20
Correct Answer: 400
Explanation:
Let the numbers be x and y.
Then, xy = 9375 and x/y = 15.
=>
=> y = 25
=> x = 15y = 15 x 25 = 375.
Sum of the numbers = 375 + 25 = 400.
Correct Answer: 24
Explanation:
Let the ten's digit be x.
Then, unit's digit = x + 2.
Number = 10x + (x + 2) = 11x + 2
Sum of digits = x + (x + 2) = 2x + 2.
(11x + 2) (2x + 2) = 144
=> 22x^2+26x-140=0
=> (x - 2)(11x + 35) = 0
=> x = 2
Hence, Required Number = 11x + 2 = 24
Correct Answer: 8/11
Explanation:
Let the numerator be x Then, denominator = x + 3.
Now. (x + 4)/(x + 3) +4 = 4/5 <=> 5 (x + 4) = 4(x + 7)
=> x = 8.
The fraction is 8/11.
Correct Answer: 3
Correct Answer: 9
Explanation:
Let the numbers be x and y. Then, 2x + 3y = 39...(i)and 3x + 2y = 30 ...(ii)
On solving (i) and (ii), we get : x = 6 and y = 9.
larger number = 9
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