Let the average of 8 men be x. Age of new man be N.
Total age of 8 men = 8x
? x + 4 = ((8x ? 30) + N)/8
? 8x + 32 = 8x ? 30 + N
? N = 32 + 30
? N = 62
Ans.
Currently :
A+B+C+D = 76
According to ques , after 7 years
A+B+C+D = 7x+6x+5x+8x = 76+7*4
26x = 76 + 28
X = 104/26
x = 4
C?s present age = 5x ? 7 =20 ? 7
= 13
Let the present ages of A & B to be ?a? & ?b? respectively.
Hence, 2 years ago, their ages must have been (a-2) & (b-2) respectively.
Average of their ages at that time = 26
Hence,
[(a-2)+(b-2)]/2 = 26
(a-2)+(b-2) = 52
a+b = 56
Age of A, 5 year hence = 40 years
Hence, (a+5) = 40
a = 35 years
Hence, b = 56 - 35 = 21 years
B = (C-5)
Hence, C = 21+5 = 26 years
Age difference between A & C = 35 - 26 = 9 years.
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