Quantity I= Let 3 year ago the age of A and B be 3x and 4x respectively
Then ATQ 3x+5+4x+5=45 X=5
Hence present age of A=3x+3=18year
Quantity II== Let 5 year ago the age of p and q be 3x and 4x respectively
Then ATQ
3x+11=4x+5
X=6 Hence present age of P=3x+5=23
Hence Quantity I < Quantity II
4th observation i.e., 8 is the median.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.