According to the given data,
(V + R)/2 = 24
Now, after joining of Veerender,
V + R + D)/3 = 25.5
Hence, Veerender Age = 3(25.5) - 2(24) = 76.5 - 48 = 28.5 years.
(A+B) - (B-C) = 12 <=> A - C = 12.
From the given statements A, B & C
Let the present age of Teja = P
Raju present age = P + 4
Sita's present age = 2(P + 4)
Average of ages of Sita & Teja = 19
=> (2P + 8 + P)/2 = 19
= 3P + 8 = 38
=> P = 30/3 = 10
Hence, the present age of Teja = P = 10 yrs.
Therefore, by using all the three statements A, B & C we can find the age of Teja.
Let the present ages of the mother and daughter be 2x and x years respectively.
Then, (2x - 18) = 3(x - 18) => x = 36
Required sum = (2x + x) = 108 years.
At the time of marriage, let Sudeer's age be 4x, then Swetha's age is 3x
12 years after:
Age of Sudeer = 4x+12
Age of Swetha = 3x+12
Now the equation is 3x+12=5/6(4x+12)
Solving equation we get x=6
Hence Swetha got married at the age of 18.
Let age of retirement = S
so according to the given condition 25000(x-20)
=10000 x 3 + 12000 + 14000 + 16000 + 18000 + 20000 + 22000 + 24000 + 26000 + 28000 + 30000 + 30000(S-33)
= 30000 + 210000 + 30000S-990000
= 30000S - 750000
or 25000S - 500000 = 30000x - 750000
or 5000x = 250000
or S = 50 yrs.
Let the present ages be K,M
Given K/M = 4/5
5K - 4M = 0 ......(1)
Also given that,
M - (K + 5) = 3
M - K = 8 .........(2)
Then, by solving (1) & (2)
M = 40 yrs and K = 32 yrs
Hence, Total of ages = 40 + 32 = 72 yrs
Difference of ages = 40 - 32 = 8 yrs.
Given the ages of Sunitha and Pranitha are 40 years and 60 years.
Let before 'm' years, their ages be in the ratio of 3 : 5
ATQ,
=> 200 - 5m = 180 - 3m
=>2m = 20
=> m = 10 years.
Given Karthik?s age = 32 years
Karthik?s son age = 7 years
Difference between their ages = K - S = 32 - 7 = 25 years ?.(1)
Now, required K = 2S ??(2)
Put (2) in (1)
2S - S = 25
=> S = 25 years
Hence, at the age of 25 years of Karthik?s son, Karthik will be twice as his son?s age.
25 - 7 = 18 years
Therefore, after 18 years the father be twice as old as the son.
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