From the given statements A, B & C
Let the present age of Teja = P
Raju present age = P + 4
Sita's present age = 2(P + 4)
Average of ages of Sita & Teja = 19
=> (2P + 8 + P)/2 = 19
= 3P + 8 = 38
=> P = 30/3 = 10
Hence, the present age of Teja = P = 10 yrs.
Therefore, by using all the three statements A, B & C we can find the age of Teja.
Let the present ages of the mother and daughter be 2x and x years respectively.
Then, (2x - 18) = 3(x - 18) => x = 36
Required sum = (2x + x) = 108 years.
Let the daughter age be 'x'
Therefore, Son age = 5x, Mother age = 25x, Person age = 50x.
Thus we get, x+5x+25x+50x = 81
81x = 81
x = 1
Daughter's age = 1, Son's = 5, Mother's = 25, Person's age = 50.
Let present ages of Sumit=w, Krishna=x, Rishabh=y and Rohit=z , then
w+x+y = 43x3 = 129 ---(i) and
w+y+z = 49x3 = 147 ---(ii)
Subtracting (i) from (ii), (w+y+z) - (w+x+y)=147 -129 , z- x =18 ---(iii)
Given Rohit's age => z = 54, so from (iii), x = 54-18 = 36
Let the age of sushma be x and
the age of her son is y
Then five years before x-5=5(y-5) ...(1)
Five years hence x+5 = 3(y+5)-8 .....(2)
By soving (1) & (2), we get
5y - 15 = 3y + 7
y = 11 => x = 35
Therefore, the age of Sushma = 35 and her son = 11.
(A+B) - (B-C) = 12 <=> A - C = 12.
According to the given data,
(V + R)/2 = 24
Now, after joining of Veerender,
V + R + D)/3 = 25.5
Hence, Veerender Age = 3(25.5) - 2(24) = 76.5 - 48 = 28.5 years.
At the time of marriage, let Sudeer's age be 4x, then Swetha's age is 3x
12 years after:
Age of Sudeer = 4x+12
Age of Swetha = 3x+12
Now the equation is 3x+12=5/6(4x+12)
Solving equation we get x=6
Hence Swetha got married at the age of 18.
Let age of retirement = S
so according to the given condition 25000(x-20)
=10000 x 3 + 12000 + 14000 + 16000 + 18000 + 20000 + 22000 + 24000 + 26000 + 28000 + 30000 + 30000(S-33)
= 30000 + 210000 + 30000S-990000
= 30000S - 750000
or 25000S - 500000 = 30000x - 750000
or 5000x = 250000
or S = 50 yrs.
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