Let present ages of Sumit=w, Krishna=x, Rishabh=y and Rohit=z , then
w+x+y = 43x3 = 129 ---(i) and
w+y+z = 49x3 = 147 ---(ii)
Subtracting (i) from (ii), (w+y+z) - (w+x+y)=147 -129 , z- x =18 ---(iii)
Given Rohit's age => z = 54, so from (iii), x = 54-18 = 36
Let the age of sushma be x and
the age of her son is y
Then five years before x-5=5(y-5) ...(1)
Five years hence x+5 = 3(y+5)-8 .....(2)
By soving (1) & (2), we get
5y - 15 = 3y + 7
y = 11 => x = 35
Therefore, the age of Sushma = 35 and her son = 11.
Let present ages of Sushanth = w, Krish = x, Rishi = y and Rohit = z , then
w + x + y = 43 x 3 = 129 ---(i) and
w + y + z = 49 x 3 = 147 ---(ii)
Subtracting (i) from (ii), (w+y+z) - (w+x+y) = 147 - 129 , z - x = 18 ---(iii)
Given Rohit's age=z=54, so from (iii), x = 54 - 18 = 36.
Therefore, Krish age is 36 years.
Anu = (Raj + 5) + 9
= Raj + 14 -------- (I)
Raj = (Renu - 4) + 7
= Renu + 3 ------- (II)
Raj's age = 19 + 3 = 22 years
After 5 years Anu's age = 22 + 14 + 5 = 41 years
Total age seven persons = (26 x 7)years
Total age of the first three persons and the last three persons are (19 x 3) years and (32 x 3) years respectively.
Age of the person sitting in the middle of the row = 26 x 7 - 19 x 3 - 32 x 3 = 182 - 57 - 96 = 29 years.
Let the daughter age be 'x'
Therefore, Son age = 5x, Mother age = 25x, Person age = 50x.
Thus we get, x+5x+25x+50x = 81
81x = 81
x = 1
Daughter's age = 1, Son's = 5, Mother's = 25, Person's age = 50.
Let the present ages of the mother and daughter be 2x and x years respectively.
Then, (2x - 18) = 3(x - 18) => x = 36
Required sum = (2x + x) = 108 years.
From the given statements A, B & C
Let the present age of Teja = P
Raju present age = P + 4
Sita's present age = 2(P + 4)
Average of ages of Sita & Teja = 19
=> (2P + 8 + P)/2 = 19
= 3P + 8 = 38
=> P = 30/3 = 10
Hence, the present age of Teja = P = 10 yrs.
Therefore, by using all the three statements A, B & C we can find the age of Teja.
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