Let the age of ruler is x so that of son = x/2 (given)
Now according to the given condition
(x/6) + (x/12) + (x/7) + 5 + (x/2) + 4 = x
=> x = 84
Let us consider Karthik as K1 and Kalyan as K2.
Given
and K2 - (K1 + 5) = 3
K2 - K1 = 8
K2 = 8 + K1
Now,
=> K1 = 32 years
Therefore K2 = 40 years.
K1 + K2 = 72 years.
Let Kumar?s present age be "x" years and Sailesh?s present age be "y" years.
Then, according to the first condition,
x - 10 = 3(y - 10) => x - 3y = - 20 ........(1)
Now, Kumar?s age after 10 years = (x + 10) years.
Sailesh?s age after 10 years = (y + 10) years.
(x + 10) = 2 (y + 10) => x - 2y = 10 ......(2)
Solving (1) and (2),
we get x = 70 and y = 30
Kumar?s present age = 70 years and Sailesh?s present age = 30 years.
Sum of ages of husband, wife and child= (24 × 3) + 9 = 81 years
Sum of ages of wife and child => 25 × 2 + 10 = 50 + 10 = 60 years
Age of husband = 81 - 60 = 21 years.
Ram age when he was born = 0 years
=> His brother's age = 6 year
=> His father's age = brother age + 32years = 6+32 = 38
=> His mother's age = father's age - 3 = 35
So sister's age = 35-25 = 10years.
Let the the age of the elder boy = E
Let the the age of the younger boy = Y
Given that Y = cube root of EY
=>
= EY => E =
.....(1)
By the condition of number replacement the age of the father is YE
The Mother's age = EY/2
But she is 3 years less than father => EY/2 + 3 = YE
2YE = EY + 6 ......(2)
Then now from the given options we can identify which satisfies the all the conditions.
Here Y =2 and E = 4 satisfies all the conditions.
Let the present age of Raj and Rajitha be 4x and 9x.
Then, according to question,
9x = 2(9x-12)-3 => 9x = 27 => x = 3
Raj's present age = 4x = 12yrs,
After 5 years Raj's age will be 12 + 5 = 17 yrs.
Let Rajan's present age be 'x' years.
=> Then his daughter's present age is = x/3 years.
His mother's present age = 13x/9 years
Now, according to the question,
x + x/3 + 13x/9 = 125
=> x = 125x9/25 = 45
Therefore, required difference = 13x/9 - x/3 = 13x - 3x/9 = 10x/9
=> 10 x 45/9 = 50 years.
12 year old Manish is three times as old as his brother Rajeev who must be 4 years old.
Diff in ages = 8 years.
when Rajeev will become 8 years old, Manish will be 16 yrs old and he will be twice as old as Rajeev.
Let the age of the youngest child is 'X' years.
Then the child elder than the yongest is 'X + 3' yrs
Since each have 3yrs difference upto 5 children
And given that
=> X + X+3 + X+6 + X+9 + X+12 = 50
=> 5X + 30 = 50
=> X = 4 yrs.
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