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- Question
The average age of 80 boys in a class is 15. The average age of group of 15 boys in the class is 16 and the average of another 25 boys in the class is 14. What is the average age of the remaining boys in the class ?
Options- A. 12.24 yrs
- B. 13.25 yrs
- C. 16 yrs
- D. 15.25 yrs
- Correct Answer
- 15.25 yrs
ExplanationTotal ages of 80 boys = 15 x 80 = 1200 yrs.
Total age of 16 boys = 15 x 16 = 240 yrs
Total age of 25 boys = 14 x 25 = 350 yrs.
Average age of remaining boys = 1200 - (240+350) / 80 - (25+15) = 610/41 = 15.25 yrs. - 1. Sony is one-fifth the age of her mother 15 years ago and Sony?s brother is three-fifth the age of his mother 10 years ago. If the sum of Sony and her brother?s ages is 31 then how old is Sony's mother ?
Options- A. 40
- B. 50
- C. 60
- D. 70 Discuss
- 2. Avanthi?s age is 1/6th of her father?s age. Her father?s age will be twice of Kapil?s age after 10 years. If Kapil?s eighth birthday was celebrated two years ago, then what is Avanthi?s present age ?
Options- A. 6 years
- B. 4 years
- C. 7 years
- D. None Discuss
- 3. Sweety is 54 years old and her mother is 80. How many years ago was Sweety's mother three times her age?
Options- A. 20
- B. 41
- C. 26
- D. 33 Discuss
- 4. In a joint family, there are 24 members whose age is decreased by 4 months, when one girl aged 24 years is replaced by a new boy. Find the age of the new boy ?
Options- A. 18 years
- B. 12 years
- C. 15 years
- D. 16 years Discuss
- 5. The age of Manisha and Sudeshna are in the ratio of 5 : 6 respectively. After 8 years the ratio of their ages will be 7 : 8. What is the difference of their ages ?
Options- A. 6
- B. 4
- C. 8
- D. 10 Discuss
- 6. The ratio of present ages of Hema and Chinnu is 13:17. Four years ago the ratio of their ages was 11:15. What will be the ratio of their ages six years hence ?
Options- A. 3 : 7
- B. 7 : 9
- C. 4 : 5
- D. 1 : 3 Discuss
- 7. A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's husband age is ?
Options- A. 45
- B. 24
- C. 42
- D. 54 Discuss
- 8. A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?
Options- A. 45, 10
- B. 10, 50
- C. 9, 50
- D. 50, 15 Discuss
- 9. Ayush was born two years after his father's marriage. His mother is five years younger than his father but 20 years older than Ayush who is 10 years old. At what age did the father get married ?
Options- A. 25 years
- B. 24 years
- C. 23 years
- D. 22 years Discuss
- 10. Mary is 12 years younger to Pinky. After 3 years, the ratio of their ages will be 5:8. If the present age of Sam is the sum of ages of Mary and Pinky, then what was the age of Sam 15 years back ?
Options- A. 31 years
- B. 37 years
- C. 46 years
- D. 29 years Discuss
Problems on Ages
Search Results
Correct Answer: 50
Explanation:
Sony and her brother's age sum is 31
Let Sony's mother's age be 'x'.
Now the conditions given for both of their ages related to their mom is
1/5(x-15) + 3/5(x-10) = 31
x-15 + 3x-30 = 155
4x-45 = 155
4x = 200
x = 50
So, Mother's age = 50.
Cross verification : 15 years ago age = 35 => Sony age = 7
10 years ago age = 40 => bro age = 24
Sum = 24 + 7 = 31.
Correct Answer: None
Explanation:
As given Kapil's 8th birthday was celebrated 2 years ago,
Kapil?s present age = 8 + 2 = 10 years.
Father's age is twice of Kapil?s age after 10 years.
=> F + 10 = 2 (K + 10) = 2 (10+ 10)
F = 30years,
Avanthi's age =1/6(F) = 30/6 = 5 years.
Correct Answer: 41
Explanation:
Given P = 54 and M = 80
According to the question,
Let ?A? years ago, M = 3P
=> M - A/P - A = 3
=> 80 - A = 3(54 - A)
=> 80 - A = 162 - 3A
=> 2A = 82
=> A = 41
Therefore, A = 41 years ago Sweety?s mother was 3 times of Sweety?s age.
Hence, at the age S = 13 and M = 39.
Correct Answer: 16 years
Explanation:
Age of new boy = (Age of moved girl) ? (Number of family members × Decreased in average)
= 24 ? 24×4/12
= 24 ? 8
= 16 years.
Correct Answer: 4
Explanation:
Let the age of Manisha and Sudeshna is 5x and 6x years respectively.
According to the given data,
5x+8/6x+8 = 7/8
42x + 56 = 40x + 64
x = 4
Required Difference of their ages = (6 × 4) ? (5 × 4)
= 4 years.
Correct Answer: 4 : 5
Explanation:
Let their present ages be 13x and 17x.
Then, 13x-4/17x-4 = 11/15.
Solving this, we get x = 2.
Required ratio = 13x2 + 6/17x2 + 6 = 32/40 = 4/5.
Correct Answer: 54
Explanation:
By trial and error method from the given options,
as 54 - 45 = (1/11) x (45+54) = 99/11 = 9
Hence this satisfies the given conditions.
Then the woman's husband age is 54.
Correct Answer: 9, 50
Explanation:
Let the age of A = A, B = B and C = C
From given
A = 3B
4 years ago,
C-4 = 2(A-4);
After 4 years
A + 4 = 31;
A = 27;
sub in above B, we get B = 9
C = 2(27 - 4) + 4 = 46 + 4 = 50
Hence B = 9yrs and C = 50yrs.
Correct Answer: 23 years
Explanation:
Ayush's present age = 10 years.
His mother's present age = (10 + 20) years = 30 years.
Ayush's father's present age = (30 + 5) years = 35 years.
Ayush's father's age at the time of Ayush's birth = (35 - 10) years = 25 years.
Therefore Ayush's father's age at the time of marriage = (25 - 2) years = 23 years.
Correct Answer: 31 years
Explanation:
Let the present age of Pinky be x years
Then the age of Mary is x - 12 years
After 3 years,
Ratio of
8x - 72 = 5x +15
=> 3x = 87
=> x = 29
=> Age of Pinky = 29 years
=> Age of Mary = 29 - 12 = 17 years
Present age of Sam = 29 + 17 = 46
Before 15 years Sam age = 46 - 15 = 31 years.
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