X= 2/3Y
=> Y= 3/2X
Aage of X after 6 years = 46 years
So present age of X = 46-6 = 40 years
Now, present age of Y = 3/2 * 40 = 60 years.
29 x 2 = 58
20 x 3 = 60
-----------
2 years
Therefore, the age of child is 2 years.
Present age of Sony = 24 + 4 = 28 years
After 5 years Renuka's age = 7×5 + 5 = 40 years
Let Hari Ram's present age = x
Then, his son's age = x/3
Father's age = 5x/2
Now the required difference =
According to the given data,
P + Q = 41 ......(1)
R - 1 = P + 2
R = P + 3
and
P + 4 = Q - 1
=> Q = P + 5 ....(2)
From (1)&(2)
P = 18
Q = 18 + 5 = 23
R = 18 + 3 = 21
=> P/S = 3/4
=> S = 4/3 x 18 = 24
Required Difference = S - R = 24 - 21 = 3.
Let present Anirudh's age be 'A' and Bhavana's age be 'B'
Given seven years, their ratio is 7:9
=> A-7 : B-7 = 7 : 9
=> 9A - 7B = 14 .......(1)
And given,
Chandhu is 12 years older than A nad 12 years younger than B
=> C = A + 12....(2)
=> B = C + 12
=> B = A + 12 + 12 .....(From (2))
=> B = A + 24 ....(3)
Put (3) in (1)
9A - 7(A+24) = 14
9A - 7A - 168 = 14
2A = 182
=> A = 91 years
=> C = A + 12 = 91 +12 = 103 years.
Let the age of Manisha and Sudeshna is 5x and 6x years respectively.
According to the given data,
5x+8/6x+8 = 7/8
42x + 56 = 40x + 64
x = 4
Required Difference of their ages = (6 × 4) ? (5 × 4)
= 4 years.
Age of new boy = (Age of moved girl) ? (Number of family members × Decreased in average)
= 24 ? 24×4/12
= 24 ? 8
= 16 years.
Given P = 54 and M = 80
According to the question,
Let ?A? years ago, M = 3P
=> M - A/P - A = 3
=> 80 - A = 3(54 - A)
=> 80 - A = 162 - 3A
=> 2A = 82
=> A = 41
Therefore, A = 41 years ago Sweety?s mother was 3 times of Sweety?s age.
Hence, at the age S = 13 and M = 39.
As given Kapil's 8th birthday was celebrated 2 years ago,
Kapil?s present age = 8 + 2 = 10 years.
Father's age is twice of Kapil?s age after 10 years.
=> F + 10 = 2 (K + 10) = 2 (10+ 10)
F = 30years,
Avanthi's age =1/6(F) = 30/6 = 5 years.
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