Let varun's age = x yrs.
From the given conditions,
x+1 = 2(x-12)
x = 25 years.
Let the present ages of A and B be 'x' and 'y' respectively
From the given data,
[(x-2) + (y-2)]/2 = 26
=> x+y = 56
But given the age of A, 5 years hence is 40 yrs => present age of A = 40 - 5 = 35 yrs
=> x = 35 => y = 56 - 35 = 21
=> Age of B = 21 yrs
Given B is 5 years younger to C,
=> Age of C = 21 + 5 = 26 yrs
=> Required Difference between ages of A and C = 35 - 26 = 9 yrs.
Let the present age of Deepa = 5p
Let the present age of Hyma = 6p
After four years their ratio = 6 : 7
=>
=> 35p + 28 = 36p + 24
=> p = 4
Therefore, the difference between their ages = 24 - 20 = 4 years.
Let Mohan present age = p
ATQ,
5/6 x p = p - 5
p = 30
His wifes age = 30 - 3 = 27 yrs.
Present total age of the members = 26(5) = 130 years.
Present age of the youngest member = 10 years
Present total age of the remaining four members = 130 -10 = 120 years
Their average age at the time of the birth of the youngest member = = 30 - 10 = 20 years.
Let the Present age of arun is x
Gokul's age = 5-2 = 3
x-6/18 = 3
x-6 = 54
x = 60
Arun's present age = 60 years
Let Shilpa's present age is p years
According to question,
p = 4(x+4) ? 4(x?4)
p = 4x+16 ? 4x+16
p = 32
Shilpa's present age = 32 years
Rajeev is four years older than Shilpa
=> Shilpa's present age = Rajeev's age 4 years before.
=> Rajeev's age 4 years before = 32 years.
Given the average age of couple and their son = 40
=> Sum of age (H +W +S) = 40×3
Let the age of daughter in law at the time of marriage = D years
Now after 10 years,
(H + S +W) + 3×12 + D +12 + 10 = 38×5
178 + D = 190
D = 190 -178 = 12 years
Let Ishika and her daughter present ages be p and q
From the given data,
p = 4/3(p - 9)
=> p = 36 years
Hence, Ishika's present age = 36 years and
Her daughter's present age = 1/6 x 36 = 6 years
Now, required her daughter?s age three years ago = 6 - 3 = 3 years.
Let number of boys = x , Let number of girls = y
Total numbers of students = x + y
(x + y) × 15.8 = 16.4x + 15.4y
0.6x = 0.4y
x/y = 0.4/0.6 = 2/3
Ratio of boys and girls in the class is 2:3
Let Anushka age = X
Charu latha 12 yrs older than Anushka so Charu latha age = x+12
Kajal is thrice as old as Anushka so Kajal age = 3x
The ages of Anushka, Kajal and Charu latha together are 57 years
i.e x + (x+12) + 3x = 57
=> 5x = 45
:- x = 9
Anushka age = 9
Kajal age = 3x = 27
Charu latha age = x+12 = 21
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.