Let the present ages of Mahesh, Nilesh and Ramesh be k, l and m respectively.
k/l = 5/x ------ (1)
k = m - 18 ------ (2)
m + 9 = 47 ------ (3)
k - l = m ----- (4)
(3) => m = 47 - 9 = 38 years
(2) => k = 38 -18 = 20 years
(1) => 20/l = 5/x => l = 4x
(4) => 4x - 20 = 38
=> 4x = 58 => x = 14.5
Let Raju's age at the time of his marriage = X years
Then from given data
=> X + 8 = 6/5 X
X = 40.
Since got married 8 years ago, his present age = 48
His sister is 10 years younger => 48 - 10 = 38 years.
Given sum of present ages of A, B, C & D
A + B + C + D = 176
and also given that,
(A-4) : (B-4) : (C-4) : (D-4) = 11 : 9 : 6 : 14
Let the ratio = x
=> A-4 + B-4 + C-4 + D-4 = 11x + 9x + 6x + 14x
=> (A + B + C + D ) - 16 = 40x
=> 176 - 16 = 40x
=> x = 4
=> A = 44 + 4 = 48
=> B = 40
=> C = 28
=> D = 60
Therefore, from the above conclusions
D is eldest with 60 years and C is youngest with 28 years of ages.
Given R + S + M + D = 76
=> R+7 : S+7 : M+7 : D+7 = 7:6:5:8
=> Let the ratio = x
=> M+7 = 5x
=> M = 5x-7
=> R = 7x-7
=> S = 6x-7
=> D = 8x-7
=> R + S + M + D = 76
=> 7x-7 + 6x-7 + 5x-7 + 8x-7 = 76
=> 26x - 28 = 76
=> 26x = 104
=> x = 4
=> Mahesh's present age = 5x-7 = 20 - 7 = 13 years.
Let, Ages of Vijaya and Simran ? 1 year ago was 4A and A years correspondingly.
Then, [(4A + 1) + 6] ? [(A + 1) + 6] = 9
3A = 9 => A = 3
Needed Ratio = (4A + 1) : (A + 1) = 13 : 4
Let the present ages of Ajay and Vijay be 'A' and 'V' years respectively.
=> A - 8 = 4/3 (V - 8) and A + 8 = 6/5 (V + 8)
=> 3/4(A - 8) = V - 8 and 5/6(A + 8) = V + 8
V = 3/4 (A - 8) + 8 = 5/6 (A + 8) - 8
=> 3/4 A - 6 + 8 = 5/6 A + 20/3 - 8
=> 10 - 20/3 = 10/12 A - 9/12 A
=> 10/3 = A/12 => A = 40.
Let the Present age of arun is x
Gokul's age = 5-2 = 3
x-6/18 = 3
x-6 = 54
x = 60
Arun's present age = 60 years
Present total age of the members = 26(5) = 130 years.
Present age of the youngest member = 10 years
Present total age of the remaining four members = 130 -10 = 120 years
Their average age at the time of the birth of the youngest member = = 30 - 10 = 20 years.
Let Mohan present age = p
ATQ,
5/6 x p = p - 5
p = 30
His wifes age = 30 - 3 = 27 yrs.
Let the present age of Deepa = 5p
Let the present age of Hyma = 6p
After four years their ratio = 6 : 7
=>
=> 35p + 28 = 36p + 24
=> p = 4
Therefore, the difference between their ages = 24 - 20 = 4 years.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.