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- Question
Raju got married 8years ago. His present age is 6/5 times his age at the time of his marriage Raju's sister was 10years younger to him at the time of his marriage. The present age of Raju's sister is ?
Options- A. 30
- B. 32
- C. 38
- D. None
- Correct Answer
- 38
ExplanationLet Raju's age at the time of his marriage = X years
Then from given data
=> X + 8 = 6/5 X
X = 40.
Since got married 8 years ago, his present age = 48
His sister is 10 years younger => 48 - 10 = 38 years.
- 1. Find the sum 3/10 + 5/100 + 8/1000 in decimal form?
Options- A. 0.853
- B. 0.358
- C. 3.58
- D. 8.35 Discuss
- 2. The auto-rickshaw fare consists of a fixed charge together with the charge for the distance covered. For a journey of 10 km, the charge paid is ?85 and for a journey of 15 km, the charge paid is ?120. The fare for a journey of 25 km will be
Options- A. ?175
- B. ?190
- C. ?180
- D. ?225 Discuss
- 3. A and B started a business in partnership investing Rs. 20,000 and Rs. 15,000 respectively. After six months, C joined them with Rs. 20,000. What will be B's share in total profit of Rs. 25,000 earned at the end of 2 years from the starting of the business?
Options- A. Rs. 7500
- B. Rs. 9000
- C. Rs. 9500
- D. Rs. 10,000 Discuss
- 4. Two-fifths of one -fourth of three -seventh of a number is 15. What is half of that number?
Options- A. 96
- B. 196
- C. 94
- D. None of these Discuss
- 5. Which of the following is a leap year?
Options- A. 1146
- B. 1254
- C. 2100
- D. 1128 Discuss
- 6. A number consists of two digits. If the digits interchange places and the new number is added to the original number, then the resulting number will be divisible by:
Options- A. 3
- B. 5
- C. 9
- D. 11 Discuss
- 7. At what time between 4 : 30 and 5 will the hands of a clock be in a straight line?
Options- A. 50 minutes past 4
- B. 42 minutes past 4
- C. 54 6 minutes past 4 11
- D. 46 minutes past 4 Discuss
- 8. How many 3-digits numbers are completely divisible by 6?
Options- A. 149
- B. 150
- C. 151
- D. 166 Discuss
- 9. In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with remaining meal?
Options- A. 56
- B. 45
- C. 30
- D. 27 Discuss
- 10. Cost of 1 chair is Rs. 214 and cost of one table is Rs. 937, then what is the approximate cost of 6 dozen chairs and 4 dozen tables?
Options- A. Rs. 60000
- B. Rs. 58000
- C. Rs. 55000
- D. Rs. 62000 Discuss
More questions
Correct Answer: 0.358
Explanation:
3/10 + 5/100 + 8/1000
= 0.3 + 0.05 + 0.008
= 0.358
Correct Answer: ?190
Explanation:
Let use assume the fixed charge = ? a
and charge for 1 km is ? = b
According to question,
for 10 KM journey charge paid = 85
a + 10 x b = 85
a + 10b = 85 .........................(1)
for 15 KM journey charge paid = 120
a + 15b = 120.........................(2)
Subtract the equation (1) from equation (2). we will get,
a + 15b - a - 10b = 120 - 85
5b = 35
b = 7
Put the value of b in equation (1). we will get
a + 10 x 7 = 85
a = 85 - 70
a = 15
Charges for 25 km = a + 25 x b
Put the value of a and b in above equation.
Charges for 25 km =15 + 25 x 7 = 15 + 175 = 190
Charges for 25 km =?190
Correct Answer: Rs. 7500
Explanation:
| ∴ B's share = Rs. | ❨ | 25000 x | 3 | ❩ | = Rs. 7,500. |
| 10 |
Correct Answer: None of these
Explanation:
Let us assume the number is P.
According the question,
three -seventh of a number = 3/7 x P
one -fourth of three -seventh of a number = 1/4 x 3/7 x P
Two-fifths of one -fourth of three -seventh of a number = 2/5 x 1/4 x 3/7 x P
? 2/5 x 1/4 x 3/7 x P = 15
? 2 x 1 x 3 x P = 15 x 7 x 4 x 5
? P = 15 x 7 x 4 x 5 / 2 x 3
? P = 5 x 7 x 2 x 5
? P = 350
? P /2 = 350/2
? P /2 = 175
Correct Answer: 1128
Explanation:
The century divisible by 400 is a leap year. 2100 is not divisible by 400 hence is not a leap year so 2100 is not a leap year, out of remaining 1128 is divisible by 4, so 1128 is a leap year.
Correct Answer: 11
Explanation:
Then, number = 10x + y.
Number obtained by interchanging the digits = 10y + x.
∴ (10x + y) + (10y + x) = 11(x + y), which is divisible by 11.
Correct Answer: 54 6 minutes past 4 11
Explanation:
Correct Answer: 150
Explanation:
First 3-digit number divisible by 6 is 102 and last 3-digit number divisible by 6 is 996.
Difference between two consecutive numbers divisible by 6 is 6.
So 3-digit numbers divisible by 6 are 102,108,114, ......., 996.
This is an Arithmetic Progression in which a = 102, d = 6 and l = 996.
where a = First Number , l = Last Number and d = difference of two consecutive numbers.
Let the number of terms be n. So Last term = tn
Then tn = 996
Use the formula for n terms of arithmetic progression.
? a + ( n - 1) x d = 996
? 102 + (n - 1) x 6 = 996
? 6(n - 1) = 894
? (n - 1) = 149
? n = 150
? Numbers of terms = 150
Correct Answer: 30
Explanation:
Correct Answer: Rs. 60000
Explanation:
Here , Cost of 1 chair = Rs. 214 and cost of one table = Rs. 937 .
? Cost of 6 dozen chairs = 6 × 12 × 214 = Rs. 15408
and cost of 4 dozen tables = 4 × 12 × 937 = Rs. 44976
? Total cost = 15408 + 44976
Total cost = Rs. 15408 + 44976 = Rs. 60384
Total cost of chairs and tables ? Rs. 60000 (Approximately)
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