Let Ben?s age now be B
Anita?s age now is A.
(A - 6) = P(B - 6)
But A is 17 and therefore 11 = P(B - 6)
11/P = B-6
(11/P) + 6 = B
Let the present age of the man be 'P' and son be 'Q',
Given, P + Q = 64 or Q = (64 - P)
Now the man says "I am five times as old as you were, when I was as old as you are",
So, P = 5[B - (P - Q)]
We get 6P = 10Q,
Substitute value for Q,
6P = 10(64 - P),
Therefore P = 40, Q = 24.
Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 - x) - 5= 4(x - 5)
55 - x = 4x - 20
5x = 75 => x = 15
Let the Father be x years when he died
Average Age 10 years ago be A
Total Age 10 years ago = 6*A
Total Age after 10 years(Just before father's Death) = 6A + 6*10 = 6A + 60
Father Died and Baby was born => the Total number of people in the family is Same (6)
Baby born today so age of baby = 0
(6A +60 - x)/6 = 6A/6
=> A + 10 -(x/6) = A
=> x/6 = 10
=> x = 60
Therefore we can conclude that the father was 60 years old when he died.
Let Meena?s age = A.
Then Sivagami?s age = A + 2
After 6 years the total of their ages will be 7 times of what?
Not clear.
So the given data are inadequate.
Let daughter?s age = A and mother?s age = B
Given: 2A+B = 70 and A+2B = 95
Solving B, we will get B = 40.
Let x = the youngest child. Each of the other four children will then be x+3, x+6, x+9, x+12.
We know that the sum of their ages is 50 .
so, x+(x+3)+(x+6)+(x+9)+(x+12) = 50
=> x= 4
The youngest child is 4 years old.
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