P(getting prize) = 10/ (10 + 25) =2/7
Out of 9 persons,4 can be choosen in ways =126.
Favourable events for given condition = = 21.
So,required probability = 21/126 =1/6.
Let A be the event of first person hitting the target,
Let B be the event of Second person hitting a target.
Since both events are independent and both will hit the target so,
P(red ball) = 5/12
P(white ball) = 4/12
P(red or white ball) = 5/12 + 4/12 = 3/4 = 0.75
P(red cards)=26/52
P(black cards)=26/52
P(red or black cards)=26/52+26/52=1
P(heart cards)=13/52
P(diamond cards)=13/52
P(heart or diamond)=13/52+13/52=1/2
P(black ball)=3/12
P(red ball)=5/12
P(black or red)=3/12+5/12=2/3
In a leap year,there are 366 days=52 weeks and 2 days
Remaining favourable 2 days can be sunday and monday or saturday and sunday
Exhaustive number of cases =7
Favourable number of cases =2
So,required probability=2/7
Let the son's present age be x years .Then, (38 - x) = x => x= 19.
Son's age 5 years back = (19 - 5) = 14 years
Let B's present age = x years. Then, A's present age = (x + 9) years.
(x + 9) + 10 = 2(x - 10)
=> x + 19 = 2x - 20
=> x =39.
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